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3 years ago

A 1500-kg car accelerates from 0 to 30 m/s in 6.0 s. What is the minimum average power delivered by the engine?

Physics

1 answer:

nadezda [96]3 years ago

7 0

Answer:

Power, P = 112500 watts

Explanation:

It is given that,

Mass of the car, m = 1500 kg

Initial velocity of the car, u = 0

Final velocity of the car, v = 30 m/s

Time taken, t = 6 s

The minimum average power delivered by the engine is given by :

P = W/t

Where

W = work done

t = time taken

Work done = change in kinetic energy

So, $P=\dfrac{\Delta K}{t}=\dfrac{\dfrac{1}{2}m(v^2-u^2)}{t}$

$P=\dfrac{\dfrac{1}{2}\times 1500\ kg\times (30\ m/s)^2}{6\ s}$

P = 112500 watts

So, the minimum average power delivered by the engine is 112500 watts. Hence, this is the required solution.

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a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will hap

bogdanovich [222]

An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity

What will happen to the spacecraft is given by option C. from among the possible question options.

C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force

Reason:

The possible question options obtained from a similar question includes;

A. The spacecraft will move for some time then stop slowly

B. Air resistance will prevent the spacecraft from moving

C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it

D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only

The state of the space craft = Motionless

Location of the spacecraft = Deep space

Type of force applied = Quick push

The statement that describes what will happen = Required

Solution;

Let F, represent the force applied, and let Δt be the duration of the applied force, we have;

The impulse of the force, F × Δt = m·(v₂ - v₁)

Where;

m = The mass of the spacecraft

v₁ = The initial velocity of the spacecraft = 0

v₂ = Final velocity of the spacecraft

Plugging in v₁ = 0, gives;

F × Δt = m·v₂

The space craft is given a velocity, v₂, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it

Therefore, the correct option is option C. The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force

Learn more about Newton's First Law of Motion here:

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3 years ago

How much time will it take a 75w ceiling fan to convert 1500j of electrical energy into mechanical and thermal energy?

-Dominant- [34]

20h

Explanation:

Given parameters:

Electrical power = 75W

Electrical energy = 1500J

Unknown:

Time taken = ?

Solution:

Electrical power is the amount of voltage that drives current.

P = IV

Electrical energy is the voltage that drives a current per unit of time

E = IVt

E = Pt

Since time is the unknown, we can make it subject of the formula;

t = $\frac{E }{P}$ = $\frac{1500}{75}$ = 20h

Learn more:

Invention of electrical power brainly.com/question/13146914

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A ladder is balanced against a wall without moving. What must be true about this ladder?

Mandarinka [93]

Answer:a no net force

Explanation: google lol

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Just like Coke is a type of soda, __________ is a type of ___________.

gladu [14]

Answer:

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Explanation:

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3 years ago

1) At which lettered point or points is the object moving the fastest?

emmainna [20.7K]

Here we have a time-position graph with some points marked on it, and we want to analyze some points in it.

1) The object is moving the fastest in the point where the slope of the curve is the largest.

In this case, the point is D.

2) Remember that the graph evolves to the right, so, if at any point, the right side is above the left side, then at that particular point the object is moving to the left (negative x-axis)

In this case, the points are:

C, D, and E.

3) The object speeds up when the curvature of the curve changes and the slope increases, for example, from B onwards, the speed increases.

Then at point C the speed is increasing.

4) Opposite to what we said before, if the slope decreases then the object is slowing down.

In this case we can see that the slope decreases after A and after E.

5) When the object is turning around?

This is easy, we can see that the object goes to the right (positive x-axis) until it reaches B and then goes back, then at point B the object turns around.

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3 years ago