A man stands on the roof of a building of height 13.0m and throws a rock with a velocity of magnitude 34.5m/s at an angle of 26.

Question

4 years ago

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A man stands on the roof of a building of height 13.0m and throws a rock with a velocity of magnitude 34.5m/s at an angle of 26.

1^\circ above the horizontal. You can ignore air resistance. calculate the horizontal distance from the base of the building to the point where the rock hits the ground?

Physics

1 answer:

IgorC [24] · Answer 1 · 2021-12-29T02:29:53+03:00

Given that the man stands on the roof the building y =13 m high. Throws a rock with a velocity of v=34.5 m/s at an angle a=26.1 degrees above the horizon. Calculate the horizontal x distance covered by the rock. The problem can be solved using the equation of trajectory:

Y=xtan(a) + g(x^2)/2(v^2)((cos(a))^2) where g = 9.81 m/s^2

Substituting the given and solving for x= 21.65 m.