Earth takes in thermal energy from the Sun in a process called- thermal radiation. The angle between the direction of the energy and the surface it is striking is called the angle of - solar incidence.
People would rush to the store to buy supplies and there might not be enough for the "last minute noticed" people
Answer:
The pressure inside the container would increase with each additional pump.
Explanation:
- From the general gas law of ideal gases:
<em>PV = nRT,</em>
where, P is the pressure of the gas.
V is the volume of the gas.
n is the no. of moles of the gas.
R is the general gas constant.
T is the temperature of the gas.
- As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.
<em>P α n.</em>
- As gas particles are pumped into a rigid steel container, the no. of moles of the gas will increase.
So, the pressure of the gas will increase.
<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>
Answer:

Explanation:
We know, 
where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and
is difference in sum of stoichiometric coefficient of products and reactants
Here
and T = 311 K
So, ![K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}](https://tex.z-dn.net/?f=K_%7Bp%7D%3D%280.0111%29%5Ctimes%20%5B%280.0821L.atm.mol%5E%7B-1%7D.K%5E%7B-1%7D%29%5Ctimes%20311K%5D%5E%7B-1%7D%3D4.35%5Ctimes%2010%5E%7B-4%7D)
Hence value of equilibrium constant in terms of partial pressure
is 
Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation: PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.
First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
250 mL = 0.250 L
58 °C = 331 K
Also, based on the equation P = nRT ÷ V
⇒ P = (2.48 mol)(0.082 L · atm/mol · K)(331 K) ÷ 0.250 L
⇒ P = (67.31 L · atm) ÷ 0.250 L
⇒ P = 269.25 atm
Thus the pressure exerted by the gas in the container is 269.25 atm.