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Sav [38]
3 years ago
9

You need a 20% alcohol solution. on hand, you have a 240 ml of a 15% alcohol mixture. you also have 40% alcohol mixture. how muc

h of the 40% mixture will you need to add to obtain the desired solution?
Chemistry
1 answer:
juin [17]3 years ago
4 0
0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
0.4x = </span>ml of alcohol in x ml of a 40% alcohol mixture
0.2(x+240)= ml of alcohol in (x+240) ml of a 20% alcohol mixture

0.15*240 + 0.4x = 0.2(x+240)
36+0.4x=0.2x+48
0.2x = 12
x=12/0.2=120/6=20 ml  of a 40% alcohol mixture
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Answer:

The pressure inside the container would increase with each additional pump.

Explanation:

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<em>PV = nRT,</em>

where, P is the pressure of the gas.

V is the volume of the gas.

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R is the general gas constant.

T is the temperature of the gas.

  • As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.

<em>P α n.</em>

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So, the pressure of the gas will increase.

<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>

8 0
3 years ago
At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

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Here \Delta n=(2)-(2+1)=-1 and T = 311 K

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Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 mL container at 58 degrees celsius
Dvinal [7]
Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation:  PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.

First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
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Also, based on the equation   P = nRT ÷ V

⇒         P  = (2.48 mol)(0.082 L · atm/mol · K)(331 K)  ÷  0.250 L
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Thus the pressure exerted by the gas in the container is  269.25 atm.
  


7 0
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