<h2>
Answer:</h2>
<h3>#Carry On Learning</h3>
<h2>
Explanation:</h2>
<h3>I hope It's Help</h3>
Answer:
Jupiter and Saturn has ammonia clouds in its atmosphere since the molecules of ammonia gas that are present in their atmospheres condense to form clouds. However, these ammonia clouds are more visible in Jupiter than in Saturn because of their lower altitude in Saturn.
Answer:
Explanation:
1. find the molar mass (amu) of each element and add them to get the whole molar mass.
2. divide the 1 element molar mass with the whole molar mass
3. multiple by 100 and that gives you the % composition.
<h2><u><em>56-57: NaCl</em></u></h2>
1. Na(22.99amu) + Cl (35.453amu)=58.443
2(Na):
= .393
2(Cl):
= .607
3(Na): .393 * 100=39.3%
3(Cl): .607 * 100= 60.7%
<h2><u>58-60 </u>

<u /></h2>
1. K: (39.098)(2)=78.196
_ C: (12.011)(1)= 12.011
_O: (15.99)(3) = 47.997
78.196+12.011+47.997= 138.204
2:K:
= .566 <u>Step </u>3: (.566)(100)= 56.6%
2: C:
= .087 <u>Step 3</u>: (.087)(100)= 8.7%
2: O:
= .347 <u>Step 3</u>: (.347)(100) = 34.7%
<h2>
61-62 
</h2>
1. Fe (55.845)(3)= 167.535
_ O (15.999)(4) = 63.996
167.535+63.996=231.531
2: Fe:
= .724 Step 3: (.724)(100)= 72.4%
2: O :
= .276 Step 3: (.276)(100) = 27.6%
<h2>63-65

</h2>
1.
C(12.011*3)=36.033
H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064
O(15.999*3)=47.997
add them: 92.094
2: C:
= .391 Step 3: (.391)(100) = 39.1%
2: H:
= .088 step 3: (.088)(100) = 8.8%
2: O:
= .521 step 3: (.521)(100) = 52.1%
Answer:
Explanation:
In electrophilic aromatic substitution, the substituent(s) that favors electrophilic attack is said to be ortho or para to the substituent. Meta directors are deactivators. Altogether, these directors have an integral role to play in the success and regioselectivity of electrophilic aromatic substitution reactions.
From the information given: The;
Strongly deactivating meta- director ⇒ NO₂ (nitro group)
Moderately deactivating meta- director ⇒ CN (cyano group)
Strongly activating ortho-/para- director ⇒ OH (hydroxy; group)
Weakly deactivating ortho-/para- director ⇒ -X (halide group)
Weakly activating ortho-/para- director ⇒ - Ph (phenyl group)