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pychu [463]
3 years ago
13

There are 7 green marbles, 8 blue marbles, and 4 yellow marbles. What is the chance, as a fraction, of drawing a blue marble, an

d without replacing it, drawing a green marble next?
Mathematics
2 answers:
alexandr1967 [171]3 years ago
4 0
1/19 and then to draw a green marble would have to be 1/18 so I hope that helps
luda_lava [24]3 years ago
3 0
There are 19 marbles total, when you add up all the colors. There are 8 blue marbles, so that's 8 out of 19, AKA 8/19. If you draw a blue marble and don't replace it, that's one less blue marble, and one less marble in general, AKA 7/18. So, now there are 18 marbles since you have drawn the blue one and haven't replaced it. There are 7 green marbles, and the total of marbles is 18 now. So, the chances of drawing a green marble is 7/18!
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3/32

Step-by-step explanation:

One approach to doing this probelm is to evaluate all three functions F, G and H at x = 2:

F(2) = 2(2) - 1 = 3

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H(2) = (2)^2 = 4

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Then (F/G)(2) = (3/8), and (F/G/H) = -------- = 3/32

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