Data Given:
Pressure = P = ?
Volume = V = 3.0 L
Temperature = T = 115 °C + 273 = 388 K
Mass = m = 75.0 g
M.mass = M = 44 g/mol
Solution:
Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
P V = n R T
Solving for P,
P = n R T / V ------ (1)
Calculating Moles,
n = m / M
n = 75.0 g / 44 g.mol⁻¹
n = 1.704 mol
Putting Values in Eq. 1,
P = (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L
P = 18.08 atm
For neutralization of acid by a base (or vice versa), the equation should be used.
M₁V₁ = M₂V₂
where M's are the molarity and the Vs are the volume. Substituting the known values,
(0.150M)(25) = M₂(15 mL)
The value of M₂ from the equation is equal to 0.25M. Thus, the concentration of the acid is 0.25M.
Answer:
a) 6312.12 lbm
b) D = 11.843 inch
Explanation:
GIVEN DATA:
Height of person = 1.89 m = 74.41 inch
mass of person m = 89 kg = 196.211 lbm
a) person earth weight =mg
where g is acceleration due to gravity = 32.17 ft/sec^2

b) waist to height ratio = 0.5

circumference of waist =

=37.21 inch
we know that circumference is given as 
D = 11.843 inch
Answer:
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