Answer:
46 g of sodium
Explanation:
Sodium reacts vigorously with fluoride gas to form NaF as shown
2Na (s) + F2 (g) ------> 2NaF (s) (Na = 23, F = 19)
2 moles of Na reacts with 1 mole of F2 to produce NaF
By calculating the molar mass of the elements involved in the reaction then multiplied by the mole, the mass can be obtained.
23 * 2 g/mol of Na reacts with 1 * 19 g/mol of F2
46 g/mol of Na reacts with 19 g/mol of F2 to produce NaF
Since the mole ratio is 2 to 1 and 19 g of F2 is used for the reaction, 46 g of sodium will be consumed for the reaction to be achieved.
