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3 years ago

How many grams of sodium are needed to react completely with 19

Chemistry

1 answer:

gtnhenbr [62]3 years ago

6 0

Answer:

46 g of sodium

Explanation:

Sodium reacts vigorously with fluoride gas to form NaF as shown

2Na (s) + F2 (g) ------> 2NaF (s) (Na = 23, F = 19)

2 moles of Na reacts with 1 mole of F2 to produce NaF

By calculating the molar mass of the elements involved in the reaction then multiplied by the mole, the mass can be obtained.

23 * 2 g/mol of Na reacts with 1 * 19 g/mol of F2

46 g/mol of Na reacts with 19 g/mol of F2 to produce NaF

Since the mole ratio is 2 to 1 and 19 g of F2 is used for the reaction, 46 g of sodium will be consumed for the reaction to be achieved.

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What are the [H₃O⁺] and the pH of a buffer that consists of 0.20 M HF and 0.25 M KF (Kₐ of HF = 6.8X10⁻⁴)?

Charra [1.4K]

The pH of 0.20 M HF (Hydrofluoric acid) is 3.27. Whereas, [H₃O⁺] for the same is 6.8 X10 ⁻⁴

<h3>What is Hydrofluoric acid?</h3>

A hydrogen fluoride and water solution is hydrofluoric acid. HF solutions are colorless, corrosive, and acidic. The majority of fluorine-containing chemicals are made using it; examples include the substance PTFE and the widely used psychiatric drug fluoxetine. Aluminum, plastics, electrical components, pharmaceuticals, high-octane fuel, fluorescent light bulbs, and refrigerants are all made with hydrogen fluoride. The production of refrigerants uses 60% of the hydrogen fluoride used in manufacturing. corrosive due to the acid's H+ ions and poisonous due to the fluoride ions F-, which can penetrate deeply, chelate calcium and magnesium, and thus upset biological balances due to the destruction of the skin's or an eye's outermost layer.

To learn more about Hydrofluoric acid, visit:

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5 0

2 years ago

The value of the equilibrium constant for the following chemical equation is Kr 40 at 25°C. Calculate the solubility of Al(OH)s(

dedylja [7]

Answer:

0,040 M

Explanation:

The global reaction of the problem is:

Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40

The equation of equilibrium is:

K = $\frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}$

The concentration of OH⁻ is:

pOH = 14 - pH = <em>3</em>

pOH = -log [OH⁻]

[OH⁻] = 1x10⁻³

Thus:

40 = $\frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}$

<em>0,04M = $\frac{[Al(OH)_{2} ^-]}{[Al(OH)]}$ </em>

This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.

I hope it helps!

7 0

3 years ago

A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

4 years ago

If I use 4 N of force to push an object 3 m, how much work have I done? A)3J B)4N C)12J

artcher [175]

Work done by me for using force of 4 N to push an object 3 m away is 12 J.

<u>Explanation:</u>

Work done on any object is defined as the force required to displace that object from its original position. In other terms, the work done is the measure of force utilized for moving an object. So mathematically it is represented as the product of force with the displacement of the object due to that force.

$Work Done = Force \times Displacement$

Then, here it is given that force of about 4 N is used to displace the object to 3m. Thus,

$\text { Work Done }=4 \times 3=12 \mathrm{J}$

So, 12 J of work is done by me to push an object 3 m away with the force of 4 N.

8 0

3 years ago

If anyone can answer all these questions you can get 35 points

torisob [31]

Answer:

6) 225.8 g

7) 1.01 g

8) 21.624 g

Explanation:

6) Molar Mass of Lithium Bromine: 86.845

86.845 * 2.6 = 225.8 g

7) Molar Mass of Neon: 20.180

20.180 * 0.05 = 1.01 g

8) Molar Mass of Water Vapor: 18.02

18.02 * 1.2 = 21.624 g

5 0

3 years ago