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3 years ago

Which of the following changes can alter the form of a substance but does not necessarily change it to an other substance?

Chemistry

1 answer:

Goshia [24]3 years ago

8 0

Answer:

The physical changes can alter the form of a substance but does not necessarily change it to an other substance

Explanation:

The physical properties of matter is one that does not depend on composition.It just change the form of matter into another form with changing into composition.

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others.

The three states of matter are: solid, liquid, and gas. The melting point and boiling point are related to changes of the state of matter. All matter may exist in any of three physical states of matter.

Example:

When water is boiled then it change into vapors. Now the form of water is change but its composition is same like water
When water freezes into ice, now phase are different i.e water is liquid while ice is solid but both have same composition.

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. A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy

gayaneshka [121]

Answer:

The volume is 4.13793 L

Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

$density=\frac{mass}{volume}$

Density is a characteristic property of every body or substance.

The most commonly used units of density are $\frac{kg}{m^{3} }$ or $\frac{g}{cm^{3} }$ for solids, and $\frac{kg}{L}$ or $\frac{g}{mL}$ for liquids and gases.

In this case, you know:

density= 0.87 $\frac{g}{mL}$
mass= 3.6 kg= 3,600 g (being 1 kg=1,000 g)
volume= ?

Replacing:

$0.87\frac{g}{mL} =\frac{3,600 g}{volume}$

Solving:

$volume =\frac{3,600 g}{0.87\frac{g}{mL}}$

volume= 4,137.93 mL

Being 1,000 mL=1 L, then volume= 4,137.93 mL= 4.13793 L

<u><em>The volume is 4.13793 L</em></u>

5 0

4 years ago

When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J.

dsp73

We have that the work function of the metal

$\phi=1.227*10^{-18}J$

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy $K.E =3.54*10-19 J.$

Generally the equation for Kinetic energy is mathematically given as

$KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}$

$\phi=1.227*10^{-18}J$

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8 0

3 years ago

Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce

Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol$

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

$Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol$

According to the reaction shown below:-

$MgCO_3\rightarrow MgO+CO_2$

$CaCO_3\rightarrow CaO+CO_2$

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = $\frac{x}{84.3139}\ mol$

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = $\frac{x}{84.3139}\times 40.3044 \ g$

Moles of CaO = $\frac{9.66 - x}{100.0869}\ mol$

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = $\frac{9.66 - x}{100.0869}\times 56.0774 \ g$

Given that total mass of the oxide = 4.84 g

Thus,

$\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84$

$\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84$

$-694.1618435x+45673.48749\dots =40843.38968\dots$

$x=\frac{4830.09780\dots }{694.1618435}$

$x=6.9582$

Thus, the mass of Magnesium carbonate = 6.9582 g

$\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100$

$\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%$

3 0

3 years ago

Determine the number of ions produced in the dissociation of the compound listed. BaS

11Alexandr11 [23.1K]

BaS → Ba²⁺ + S²⁻
two types of ions

4 0

3 years ago

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When a radioactive sample decays for 2 half-lives the amount remaining will be ____ of the original?

mash [69]

1/4 of the original.

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3 years ago