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torisob [31]
2 years ago
7

Waves form when energy is transferred to ocean

Chemistry
1 answer:
olga_2 [115]2 years ago
7 0

Answer:

In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

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milk has a pH of 6.0 and household ammonia has a pH of 12.0. How much more acidic is milk than ammonia
iris [78.8K]

60 I think bcz if there is 1&2 they differ 10 times

3 0
3 years ago
HELP! WILL GIVE BRAINLY!!!
Contact [7]

Answer:

True

Density = mass/volume

Suppose that a block has a mass of 20 g and a volume of 20 cm^3.

Density = 20 g/20 cm^3 = 1 g/cm^3

Now, you cut the block in half. The half-block has a mass of 10 g and a volume of 10 cm^3.

The density of the half-block is

Density = 10 g/10 cm^3 = 1 g/cm^3

The density stays the same, even though the size of the sample has changed.

Explanation:

4 0
3 years ago
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What is the pH of soil ?​
Vesna [10]

Answer:

Most soils have pH values between 3.5 and 10. In higher rainfall areas the natural pH of soils typically ranges from 5 to 7, while in drier areas the range is 6.5 to 9. Soils can be classified according to their pH value: 6.5 to 7.5—neutral

Explanation:

hope this helps if not let me know have a great day

3 0
2 years ago
The standard cell potential (E°cell) for the reaction below is +1.10V. The cell potential for this reaction is ________ V when t
alexandr402 [8]

Answer: 0.94 V

Explanation:

For the given chemical reaction :

Zn(s)+Cu^{2+}(aq)\rightarrow Cu(s)+Zn^{2+}

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 298K

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = +1.10 V

E_{cell} = emf of the cell = ?

Now put all the given values in the above equation, we get:

E_{cell}=+1.10-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{2.5}{1.0\times 10^{-5}}

E_{cell}=+1.10-0.16V=0.94V

The cell potential for this reaction is 0.94 V

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3 years ago
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