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Which statement correctly describes the phosphate ion, mc031-1.jpg? It is composed of one phosphorus atom and four oxygen atoms

STatiana [176]

The phosphate ion has a formula of PO₄⁻³
It is visible that there is one phosphorus atom and four oxygen atoms. Moreover, we know that both phosphorus and oxygen are non-metallic elements, so the bonding that must be present between them is covalent bonding.
Finally, the charge of an ion is distributed over the entire ion so that it is stabilized. Thus, the answer is:
It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion

5 0

3 years ago

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A(n) _______________ is a negatively charged ion

siniylev [52]

An anion is a negatively charged ion.

Hope this helps xox :)

3 0

3 years ago

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Suppose that in the synthesis of isoamyl acetate by Fisher esterification, a student began with 6.103 grams of acetic acid and 3

Troyanec [42]

Answer:

The % yield is 90.68 %

Explanation:

Step 1: Data given

Mass of acetic acid = 6.103 grams

Mass of isoamyl alcohol = 3.728 grams

Mass isoamyl acetate obtained = 4.993 grams

Molar mass acetic acid = 60.05 g/mol

Molar mass of isoamyl alcohol = 88.15 g/mol

Molar mass of isoamyl acetate = 130.19 g/mol

Step 2: The balanced equation

C5H12O + CH3COOH → C7H14O2 +H2O Isoamyl alcohol + acetic acid ---> Isoamyl acetate + water

Step 3: Calculate moles of acetic acid

Moles acetic acid = Mass acetic acid / Molar mass acetic acid

Moles acetic acid = 6.103 grams / 60.05 g/mol

Moles acetic acid = 0.1016 moles

Step 4: Calculate moles isoamyl alcohol

Moles isoamyl alcohol = 3.728 grams / 88.15 g/mol

Moles isoamy lalcohol = 0.04229 moles

Step 5: Calculate limiting reactant

The mole ratio is 1:1 so isoamyl alcohol has the smallest number of moles. So isoamyl alcohol is the limiting reactant. It will be completely be consumed (0.04229 moles).

Acetic acid is in excess, there will be consumed 0.04229 moles.

There will remain 0.1016 - 0.04229 = 0.05931‬ moles

Step 6: Calculate moles of isoamyl acetate

For 1 mole acetic acid , we need 1 mole of isoamyl alcohol, to produce 1 mole isoamyl acetate and 1 mole of H2O

For 0.04229 moles isoamyl alcohol consumed, there will be produced 0.04229 moles of isoamyl acetate.

Step 7: Calculate mass of isoamyl acetate

Mass isoamyl acetate = moles isoamyl acetate * molar mas isoamyl acetate

Mass isoamyl acetate = 0.04229 moles * 130.19 g/mol

Mass isoamyl acetate = 5.506 grams = theoretical yield

Step 8: Calcuate % yield

% yield = actual yield / theoretical yield

% yield = (4.993 / 5.506)*100%

% yield = 90.68 %

The % yield is 90.68 %

7 0

3 years ago

The standard biological reaction Gibbs energy for the removal of the phosphate group from adenosine monophosphate is 14 kJ mol-1

nignag [31]

Answer: K = 284

Explanation:

Gibbs free energy (DG) = RT(InK)

Where :

R = Gas constant = 8.314J/K/mol = 0.008314KJmol/K

T = temperature in Kelvin = 298K

K = dissociation rate

DG = 14

DG = RT(InK)

14 = 0.008314 × 298 × (InK)

14 = 2.477572 × InK

Ink = (14 ÷ 2.477542)

InK = 5.6507619

K = 284

7 0

3 years ago

Explain how the following experimental errors affect the final calculation of the kilocalories per gram for a food item. Be spec

Ainat [17]

Answer:

a) the final kilocalories per gram for food will be less because the mass was reduced

b)the final kilocalories per gram for food will be less since

c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion

d) the final kilocalories per gram for food will be more.

Explanation:

a) the final kilocalories per gram for food will be less because the mass was reduced from 110.3 to 101.3g

b)the final kilocalories per gram for food will be less since some marshmallow fell off before the reaction

c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion

d) the final kilocalories per gram for food will be more since the thermometer that got stuck will add to the value of final kilocalories per gram

6 0

4 years ago