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JulsSmile [24]
3 years ago
12

Why is it important to use chemicals of high quality (purity) and exact(correct) concentrations in experiments?​

Chemistry
2 answers:
marishachu [46]3 years ago
8 0

Answer:

To produce good or targeted result

Darya [45]3 years ago
6 0

It is important to use chemicals of high quality and correct concentrations in experiment so that we can obtain the predictable result in an experiment

Purity of substances/chemicals is very important when performing experiments in the laboratories, because it plays an important role in the determination of the chemical properties of  substances which will have a direct effect on the result obtained from the experiment. likewise using the correct concentration of reagents

During experiments to obtain the best/predictable result in an experiment it is of best practice to make use of chemicals of high quality and also at the exact(needed) concentrations, that way the predictable result of the experiment will be obtained.

Learn more : brainly.com/question/8684258

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A scientist is investigating the structure of aluminum nitrate, which has the chemical formula Al(NO3)3. Based on the chemical f
bekas [8.4K]
The chemical formula of aluminium nitrate is - Al(NO₃)₃
cation is Al³⁺
anion is NO₃⁻
One Al atom binds to three nitrate groups 
the options given are 
2. <span>It has three aluminum (Al) atoms 
this is incorrect as there's only one Al atom 
3. </span><span>It has one NO3 group.
this is incorrect as there are three nitrate groups
4. </span><span>It has nine nitrogen (N) atoms
there are only 3 N atoms therefore this too is incorrect 
</span>therefore the correct answer is - 
It has three NO₃<span> groups


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The electrical charge of the nucleus is determined by:
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A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
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Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

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