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4 years ago

I don't understand this I'm confused

Chemistry

1 answer:

skad [1K]4 years ago

5 0

Explanation:

Sodium, or Na, is 57.47% of the composition,

Hydrogen, or H, is 2.520% of the composition,

and Oxygen, or O, is 40.001% of the composition.

This is because mass% = mass/total mass x 100%.

2. For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 5.2 moles you are trying to make by the 6 moles of water you need, and you will need 31.2 moles.

3. x = 7.2 x 4 / 2 = 14.4 mol

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Viết công thức hóa học tạo bởi Mg và O

jasenka [17]

Phương trình hóa học: 2Mg+O2->2Mgo

3 0

3 years ago

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2 will be 0.121 M

Explanation:

$ln\frac{[A_t]}{[A_0]} =-kt$

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) = -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

$\frac{A_t}{0.125} = e^{-0.03024$

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M

6 0

3 years ago

What ion is formed when an atom of magnesium (mg) loses two electrons? mg–1 mg–2 mg 1 mg 2

frez [133]

the correct answer is Mg+2

3 0

3 years ago

Read 2 more answers

??????????????????<br> Why are quantities important in the study of chemistry give an example please

slamgirl [31]

Answer:

Chemistry is the study of matter and how it behaves.

The scientific method is the general process by which we learn about the natural universe.

Explanation:

8 0

3 years ago

Aluminum has a specific heat of 0.902 j/gC. How much heat is lost when a piece of aluminum with a mass of 23.984 g cools from a

Marizza181 [45]

Answer:

Q = - 8501.99 j

Explanation:

Given data:

Specific heat of Al = 0.902 j/g.°C

Heat lost = ?

Mass of sample = 23.984 g

Initial temperature = 415°C

Final temperature = 22°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 22°C - 415°C

ΔT = -393°C

Q = m.c. ΔT

Q = 23.984 g× 0.902 j/g.°C × -393°C

Q = - 8501.99 j

8 0

3 years ago

I don't understand this I'm confused ​

I don't understand this I'm confused