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3 years ago

At what time does the box have the greatest kinetic energy

Physics

1 answer:

Y_Kistochka [10]3 years ago

3 0

Answer:

therefore, more kinetic energy! An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

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Imagine that two charged objects are the system of interest. When the objects are infinitely far from each other, the electric p

podryga [215]

Answer: Option (c) is the correct answer.

Explanation:

It is known that the expression for potential energy related to charges and distance between their separation is as follows.

$U_{q} = \frac{kq_{1}q_{2}}{r}$

where, $q_{1}$ and $q_{2}$ are two charges

r = distance of separation between the charges

k = electrostatic constant

So, when both the charges are carry the same charge and r is small then the value of potential energy will be positive in nature.

Whereas if the distance of separation between the charges is infinitely large then the potential energy calculated will be zero everywhere.

Thus, we can conclude that the statement one object is negatively charged and the other one is positively charged, is incorrect.

5 0

3 years ago

A gravitational field is generated by any object that has

WITCHER [35]

Answer:

two poles

Explanation:

5 0

3 years ago

Read 2 more answers

Please help asap. I'm terrible with atoms

11Alexandr11 [23.1K]

<span>Correct answer: more, smaller</span>

6 0

3 years ago

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Beams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. A certain gun has an elec

Natasha2012 [34]

Answer: v = 2.75 * 10^7 m/s

Explanation: Since the electric field is a uniform one and the distance is small, the motion of the electron is of a constant acceleration, hence newton's laws of motion is applicable.

From the question

E=strength of electric field = 214N/c

q=magnitude of an electronic charge = 1.609* 10^-16c

m= mass of an electronic charge = 9.11*10^-31kg

v = velocity of electron.

S= distance covered = 1cm = 0.01m

a = acceleration of electron.

F = ma but F=Eq

Eq = ma.

a = Eq/m

a = 214 * 1.609*10^-16/ 9.11 * 10^-31

a = 344.32 * 10^-16/ 9.11 * 10 ^-31

a = 3. 779* 10^16 m/s²

Before the electron is accelerated, they are always not moving, hence initial velocity (u) = 0.

By using the equation of motion, we have

v² = u² + 2aS

But u = 0

v² = 2aS

v²= 2* 3.779*10^16 * 0.01

v² = 7.558 * 10^14

v = √7.558 * 10^14

v = 2.75 * 10^7 m/s.

6 0

3 years ago

A child bounces in a harness suspended from a door frame by three elastic bands. If each elastic band stretches 0.300 m while su

WINSTONCH [101]

Answer:

The force constant for each elastic band is 77.93 N/m

Explanation:

Hooke's law of a spring or an elastic band gives the relation between elastic force (Fe) and stretching (x), the magnitude of that force is:

$F_{e}= kx$ (1)

With k, the elastic force constant. The three elastic bands support the child’s weight (W) and maintain him at rest, so by Newton’s second law for one of the elastic bands:

$\sum F=0$ (2)

$\frac{W}{3}-F_{e}=0\Rightarrow F_{e}=\frac{W}{3}$ (3)

Using (1) on (3):

$kx=\frac{W}{3}\Rightarrow k=\frac{mg}{3x}$ (4)

$k=\frac{7.15\,kg*9.81\,\frac{m}{s^{2}}}{3*0.300\,m}\simeq\mathbf{77.93\frac{N}{m}}$

8 0

3 years ago