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xxTIMURxx [149]
3 years ago
15

NUCLEAR POWER PRODUCES LESS TOXIC SULFUR THAN COAL BURNING ELECTRICITY TRUE OR FALSE

Physics
2 answers:
konstantin123 [22]3 years ago
8 0
True because a nuclear power produces tons of high level radioactive waste that has to be disposed of carefully
ExtremeBDS [4]3 years ago
6 0
That's true. Nuclear power generation produces no sulfur at all.
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Explain how the air balloon moves up and down.<br> Explain in terms of density
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3 years ago
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

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3 years ago
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5 0
3 years ago
A 87 kgkg skydiver can be modeled as a rectangular "box" with dimensions 18 cmcm ×× 47 cmcm ×× 180 cmcm . If he falls feet first
garik1379 [7]

Answer:

Therefore the terminal velocity = 1.45 m/s

Explanation:

Terminal velocity: Terminal velocity is the highest velocity of an object when it falls from rest trough a media.

V_t=\sqrt{\frac{2w}{c_d\rho A}}

V_t= terminal velocity

w = weight of the object = mg

c_d = drag coefficient=0.80

A= frontal area

\rho = media density = 1.2 kg/m³

m = mass = 8 kg

g= acceleration due to gravity = 9.8 m/s²

Front area = length× breadth

                 = (18×47)cm²

                 =846 cm²

Therefore the terminal velocity

v_t= \sqrt{\frac{2\times 87\times 9.8}{0.80\times 846 \times 1.2}

    =1.45 m/s

Therefore the terminal velocity = 1.45 m/s

8 0
3 years ago
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