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Klio2033 [76]
3 years ago
9

An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar

e the magnitude and direction of the electric field?
Physics
1 answer:
Iteru [2.4K]3 years ago
6 0
The direction of the electric field would be south. 

qE/m = 115 
<span>       E = 115*m/q </span>
<span>           = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span>           = 762.87 * 10^(-12) </span>
<span>           = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
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Given:
Stopping distance range is d = (65, 70) ft.

The stopping distance, d, obeys this formula.
d = v²/(2μg)
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Therefore
v = √(2*0.8*32.2*d) = 7.178√d

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3 0
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What is the energy equivalent of an object with a mass of 1. 05 g? 3. 15 Ă— 105 J 3. 15 Ă— 108 J 9. 45 Ă— 1013 J 9. 45 Ă— 1016 J
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Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:

E=m×c²

This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.  

In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.

In this case, you know:

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Replacing:

E= 1.05 kg× (3×10⁸ m/s)²

Solving:

<u><em>E= 9.45×10¹⁶ J</em></u>

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Learn more:

  • brainly.com/question/9477556
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Explanation:

7 0
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