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Klio2033 [76]
3 years ago
9

An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar

e the magnitude and direction of the electric field?
Physics
1 answer:
Iteru [2.4K]3 years ago
6 0
The direction of the electric field would be south. 

qE/m = 115 
<span>       E = 115*m/q </span>
<span>           = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span>           = 762.87 * 10^(-12) </span>
<span>           = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
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The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
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Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

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So \frac{\lambda }{2}=20cm

2

λ

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We have to find the speed of the wave in the string

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3 years ago
Light travels _____________ in a material with a higher index of refraction.
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4 0
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Read 2 more answers
Energy Conservation With Conservative Forces: If a spring-operated gun can shoot a pellet to a maximum height of 100 m on Earth,
crimeas [40]

Answer:

h' = 603.08 m

Explanation:

First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

Vi = Initial Velocity of Pellet = ?

Therefore,

(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

g' = acceleration due to gravity on the surface of moon = 1.625 m/s²

h' = maximum height gained by pellet on moon = ?

Therefore,

2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²

h' = (1960 m²/s²)/(3.25 m/s²)

<u>h' = 603.08 m</u>

4 0
3 years ago
Electromagnetic radiation behaves both as particles (called photons) and as waves. Wavelength (λ) and frequency (ν) are related
inessss [21]
<h2>Answer: 136.363 m</h2>

Explanation:

We can find the wavelength of the radiation produced by the microwave oven by using the following given equation:

c=\lambda.\nu   (1)

Clearing \lambda :

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Knowing \nu=2.20 GHz=2.20(10)^{6}Hz=2.20(10)^{6}s^{-1}

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\lambda=136.363m This is the wavelength of the radiation produced by the microwave

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