An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar
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Solution :
Let kg
m/s
Let and
are the speeds of the disk
and
after the collision.
So applying conservation of momentum in the y-direction,
Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.
Now applying conservation of momentum in the x-direction,
m/s
So,
= 4.33 m/s
Therefore, speed of the disk 2 after collision is 4.33 m/s