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Klio2033 [76]
3 years ago
9

An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar

e the magnitude and direction of the electric field?
Physics
1 answer:
Iteru [2.4K]3 years ago
6 0
The direction of the electric field would be south. 

qE/m = 115 
<span>       E = 115*m/q </span>
<span>           = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span>           = 762.87 * 10^(-12) </span>
<span>           = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
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