1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ghella [55]
3 years ago
10

3.50 µf capacitor has a charge with a magnitude of 4.50 µC on each parallel plate. Find the potential difference between the pla

tes.
a) 0.85 V
b) 1.29 V
c) 1.70 V
d) 2.00 V
Physics
1 answer:
n200080 [17]3 years ago
8 0

Answer:

b) 1.29 V

Explanation:

Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field

The expression for the potential difference is

Q = CV .................... Equation 1

Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.

Making V the subject of the equation,

V = Q/C................. Equation 2

Given: Q = 4.5  µC = 4.5×10⁻⁶ C, C = 3.5  µF = 3.5×10⁻⁶ F

Substituting into equation 2

V = 4.5×10⁻⁶ /3.5×10⁻⁶

V = 1.2857 V

V ≈ 1.29 V.

Hence the right option is  b) 1.29 V

You might be interested in
A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-
joja [24]

Answer:

5.25\cdot 10^{40} kg m^2/s

Explanation:

The angular momentum of the pulsar is given by:

L=m\omega r^2

where

m=2.8\cdot 10^{30} kg is the mass of the pulsar

r = 10.0 km = 1\cdot 10^4 m is the radius

\omega is the angular speed

Given the period of the pulsar, T=33.5\cdot 10^{-3} s, the angular speed is given by

\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s

And so, the angular momentum is

L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s

8 0
3 years ago
Distinguish between linear momentum and angular momentum.
Katarina [22]

Linear momentum is in a straight line and depends on the objects mass and velocity.

Angular (rotational) momentum depends on the objects mass, velocity, and radius.

7 0
3 years ago
A force of 14 N acts on a 5 kg object for 3 seconds.
DiKsa [7]

Answer: a) 42Nm b) 8.4m/s

Explanation:

Impulse is defined as object change in momentum.

Since Force = mass × acceleration

F = ma

Acceleration is the rate of change in velocity.

F = m(v-u)/t

Cross multiply

Ft = m(v-u)

Since impulse = Ft

and Ft = m(v-u)... (1)

The object change in velocity (v-u) = Ft/m from eqn 1

Going to the question;

a) Impulse = Force (F) × time(t)

Given force = 14N and time = 3seconds

Impulse = 14×3

Impulse = 42Nm

b) The object change in velocity (v-u) = Ft/m where mass = 5kg

v-u = 14×3/5

Change in velocity = 42/5 = 8.4m/s

3 0
3 years ago
Which is heavier , a kilogram of lead or a kilogram of a polystyrene beads ?​
Mars2501 [29]

Answer:

They weight the same, they're both 1 kilogram

3 0
2 years ago
Read 2 more answers
Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha
timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}.

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

1 \ kg = 1000 \ g,

Now, we can divide by 1 kg on each side

\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg},

1 = \frac{1000 \ g}{1 \ kg}.

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

mass_{human} = 68 \ kg

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}

mass_{human} = 68,000 g

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal

So, we would need 10,200  Cal per day.

3 0
2 years ago
Other questions:
  • For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
    7·1 answer
  • Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
    8·1 answer
  • How long does it take for earth to revolve around the sun?
    6·1 answer
  • What is the relationship between DNA and RNA?
    9·1 answer
  • A freight train is accelerating on a level track. The tension in the coupling between the engine and the first freight car would
    14·1 answer
  • You are trying to climb a castle wall so, from the ground, you throw a hook with a rope attached to it at 24.1 m/s at an angle o
    5·1 answer
  • How much sugar can dissolve in 25 ml of water 25 C
    7·1 answer
  • PLEASE CAN PEOPLE HELP WITH MY STUFF I SUCK AT CONCENTRAITING IN SCHOOL
    12·2 answers
  • Two formats of sources are
    11·1 answer
  • How is the centripetal force related to the tangential velocity of the mass?.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!