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Dimas [21]
3 years ago
5

7.a railway truck A of a mass of 2000kg moves westwards with a velocity of 3m/s. It collides with a stationary truck B 1200kg, l

oaded with electronic equipment of mass 300kg. The two trucks combined after collision. Ignore the effects of friction. 7.1. Write down magnitude and direction of the 'reaction force' to the weight
of truck A.
(2)
7.2. Calculate the velocity of truck B after the collision.
(5)
7.3. Calculate the magnitude of the force that the truck A exert on truck B if
the collision lasts for 0,5 s.
(4)
8. The most common reasons for rear-end collisions are too shortfollowing a
distance, speeding and failing brakes. The sketch below represents one such​
Physics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

9. A 1500kg car traveling +6m/s with a 2000kg truck at rest. The vehicles collide, but do not stick together. The car has a velocity -3m/s after the collision. What is the velocity of the truck? a. What type of collision occurred above?

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When have you experienced an increase in kinetic<br> energy within a system?
Mars2501 [29]

Answer:

If a man starts running on a boat with an acceleration a with respect to the boat, there is no external force that acts on the Boat+Man system

8 0
3 years ago
A solenoid with 435 turns has a length of 7.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find the solenoid's inductance a
OLga [1]

Answer:

Solenoid's inductance is 1.11 × 10^-8H

The average emf around the solenoid is 1.3 × 10^-5V

Explanation: Please see the attachments below

4 0
3 years ago
Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
DanielleElmas [232]

Answer:

Charge on each is 2 x 10⁻¹⁰.

Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

k = 9 x 10^9

r = 3.00 cm

= 0.03 m

q₁ = q₂

F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

q² = 4 x 10⁻²⁰

q = 2 x 10⁻¹⁰

As there is force of repulsion between the charges, the charges must be both positive or both negative.

3 0
3 years ago
A 2.5g copper penny is given a charge of -4.0*10^-9c. how mny excess electrons are on the penny?
Lyrx [107]

Answer : The excess of electrons on the penny are, 2.5\times 10^{10} electrons

Solution : Given,

Total charge = -4.0\times 10^{-9}C

Charge on electron = -1.6\times 10^{-19}C

Formula used :

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}

Now put all the given values in this formula, we get the excess of electrons present on the penny.

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-

Therefore, the excess of electrons on the penny are, 2.5\times 10^{10} electrons


7 0
3 years ago
How did Micheal Faraday discover the magnetic theory and when?​
serious [3.7K]

Answer:

Faraday made his first discovery of electromagnetism in 1821.  He took the work of Oersted and Ampère on the magnetic properties of electrical currents as a starting point and in 1831 achieved an electrical current from a changing magnetic field, a phenomenon known as electromagnetic induction.

Explanation:

6 0
3 years ago
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