Answer:
0.1 m
Explanation:
The closest distance the electrodes used in an NCV test in oerder to measure
the voltage change as a response to the stimulus is 0.1 m.
This is because the shortest observable time period is not less than the action-potential time response of 1 mili second the length traveled by the sensation during this time is 1 m sec x 100 m / s =0.1 m, which is the shortest distance the electrodes could be positioned on the nerve.
La velocidad correcta de la luz en el vacío es 300.000 km/s .
La distancia = (velocidad) x (duración de tiempo)
Duración de tiempo = 494 segundos, porque cada minuto = 60 segundos
La distancia = (300.000 km/s) x (494 s)
<em>La distancia = 148.200.000 km</em>
Answer:
215000kgm/s
Explanation:
Given parameters:
Mass of the moving body = 5000kg
Velocity = 43m/s
Unknown:
Momentum = ?
Solution:
The momentum of a body is the amount of motion a body possess.
It is mathematically expressed as:
Momentum = mass x velocity
Now:
Momentum = 5000 x 43 = 215000kgm/s
The focal length of given concave lens will be -26.85 cm
The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.
Given concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.
We have to find focal length
The focal length can be found out by following way:
Magnification = m = +1.75
m = hi/h
hi = -47 cm
1.75 = -47/h
h = -26.85 cm
So the focal length of given concave lens will be -26.85 cm
Learn more about magnification factor here:
brainly.com/question/6947486
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Answer:
True
Explanation:
I am not 100% on the answer for this question but i hope it was right
