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Dafna11 [192]
3 years ago
13

Part II. The molality of a solution is the number of moles of the solute that is dissolved in 1000 g of solvent. Using the value

s for the mass of sodium chloride, its molar mass (58.443 g/mol), and the mass of water solvent that you used, calculate and enter the molality of the sodium chloride solution to three significant digits, e.g. 0.484.

Chemistry
1 answer:
Aleks [24]3 years ago
5 0

Answer:

Explanation:

The molality of a solution, m is defined as the number of moles of the solute that is dissolved in 1 kg of solvent.

m = number of moles/kilogram of solvent

Attached is the answer and complete question.

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Nitrate ions \text{NO}_3^{-} and potassium ions \text{K}^{+}.

<h3>Explanation</h3>

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Start with the balanced chemical equation for this process:

\text{K}_2\text{CrO}_4 \; (aq) + \text{Ba}(\text{NO}_3)_2 \; (aq) \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{KNO}_3 \; (aq)

Rewrite the chemical equation as an ionic one; express all soluble salts- those with state symbol (aq)- as their constituting ions while leaving the insoluble (s) intact.

2 \; \text{K}^{+}\; (aq)+ 2\; \text{CrO}_4^{-} \; (aq) + \text{Ba}^{2+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq) \\ \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{K}^{+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq)

\text{K}^{+} and \text{CrO}_4^{-} are found on both sides of the equation by the same quantity. The two ions thus took no part in the net reaction and act as spectator ions.

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The anionic forms of Se are more stable than the forms of S, similarly to how Br⁻ is more stable than Cl⁻.

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