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lina2011 [118]
2 years ago
7

Ca(s) + O₂(g) + S(s) → CaSO4(s)

Chemistry
1 answer:
san4es73 [151]2 years ago
5 0

The mass of Calcium required to complete this reaction is 4.008 g.

  • Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
  • The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
  • In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.

In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.

So,

mass of Ca + mass of O₂ + mass of S = mass of CaSO4

Ca + 6.400 g + 3.206 g = 13.614 g

mass of Ca = 13.614 - 9.606 = 4.008 g

Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.

Learn more about mass conservation here:

brainly.com/question/2030891

#SPJ9

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Consider the complete reaction of 43.0 g of silicon with excess nitrogen gas in the reaction shown below. What mass of product f
kupik [55]
The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53

according to reaction 3 moles of Si gives 1 mole of Si3N4

so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4

molar mass of Si3N4 = 140.28 g/mole

it means that 1 mole of Si3N4 = 140.28 g

so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g
7 0
4 years ago
How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)
11Alexandr11 [23.1K]

98.56 dm^3 of oxygen at STP would be required to react completely with 38.8g of propane.

<u>Given that :</u>

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = \frac{38.8}{44} = 0.88 mole

<u>applying rule of balanced equations </u>

1 mole of propane = 5 moles of oxygen

0.88 mole of propane =  5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = 22.4 dm^3

∴Total volume of oxygen required at STP = 22.4 * 4.4 = 98.56 dm^3

Hence we can conclude that the volume of oxygen at STP required to react completely 98.56 dm^3

Learn more : brainly.com/question/16998374

5 0
2 years ago
Calculate the work done when a force of 4 N pulls a box along the floor for a distance of 0.3 m.
Yuki888 [10]

Answer:

<h2><em>1</em><em>.</em><em>2</em><em> </em><em>Joule</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>Force=</em><em>4</em><em> </em><em>N</em>

<em>Distance</em><em>=</em><em>0</em><em>.</em><em>3</em><em> </em><em>m</em>

<em>Now</em><em>,</em>

<em>work = f \times d \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 4 \times 0.3 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 1.2 \: joule</em>

<em>hope</em><em> </em><em>this </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
4 years ago
Use significant figures rule
ivolga24 [154]

Answer:

x, Z, M, H, A, K, E, I, L, R, O, W

7 0
3 years ago
Identify one factor represented in the diagram that is used to classify the ten types of clouds
Ede4ka [16]
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Middle clouds
Clouds with the prefix “alto” are middle-level clouds that have bases at 6,500 to 23,000 feet up. Altocumulus clouds are made of water droplets and appear as gray, puffy masses, sometimes rolled out in parallel waves or bands. These clouds on a warm, humid summer morning often mean thunderstorms by late afternoon. Altostratus clouds, gray or blue-gray, are made up of ice crystals and water droplets. They usually cover the sky. In thinner areas of them, the sun may be dimly visible as a round disk. Altostratus clouds often form ahead of storms that produce continuous precipitation.

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Cirrus clouds are thin, wispy clouds blown by high winds into long streamers. They are considered “high clouds,” forming at more than 20,000 feet. They usually move across the sky from west to east and generally mean fair to pleasant weather. Cirrostratus, thin, sheetlike clouds that often cover the sky, are so thin the sun and moon can be seen through them. Cirrocumulus clouds appear as small, rounded white puffs. Small ripples in the cirrocumulus sometimes resemble the scales of a fish, creating what is sometimes called a “mackerel sky.”

Vertical clouds
Cumulus clouds are puffy and can look like floating cotton. The base of each is often flat and may be only 330 feet above ground. The top has rounded towers. When the top resembles a cauliflower head, it is called “cumulus congestus.” These grow upward and if they continue to grow vertically can develop into a giant cumulonimbus, a thunderstorm cloud, with dark bases no more than 1,000 feet above ground and extending to more than 39,000 feet. Tremendous energy is released by condensation of water vapor in a cumulonimbus. Lightning, thunder and violent tornadoes are associated with them.
6 0
3 years ago
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