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Ronch [10]
3 years ago
9

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

Chemistry
1 answer:
sp2606 [1]3 years ago
7 0
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) =  0.0184 g O_{2}
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4 Which pair of ions is isoelectronic?
Softa [21]

Answer:

B. Na+ and O2-

Explanation:

Na+ plus has 10 electrons and O2- also has 10 electrons

7 0
3 years ago
If you start with 30 moles of O2, how many moles of SiO2 can you make?
Ivanshal [37]

Answer:

30moles of SiO₂

Explanation:

Given parameters:

Number of moles of O₂  = 30moles

Unknown:

Number of moles of SiO₂  = ?

Solution:

To solve this problem, we need to write the reaction expression:

       Si +  O₂  →  SiO₂  

The reaction is balanced;

      1 mole of O₂ will produce 1 mole of SiO₂

     30mole of O₂ will produce 30moles of SiO₂

7 0
3 years ago
Nitrous oxide (n2o), or laughing gas, is commonly used as an anesthetic in dentistry and surgery. how many moles are present in
Gelneren [198K]

Answer is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.

V(N₂O) = 8.4 L.

V(N₂O) = n(N₂O) · Vm.

Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.

n(N₂O) = 8.4 L ÷ 22.4 L/mol.

n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>

5 0
3 years ago
What is the mass of 2.2x10^9 molecules of CO2? *​
olga55 [171]

Answer: 9.68 x 10^10 grams.

Explanation:

Given that:

Mass of CO2 = ?

Number of molecules of CO2 = 2.2x10^9 molecules

Molar mass of CO2 = ? (let unknown value be Z)

For the molar mass of CO2: Atomic mass of Carbon = 12; Oxygen = 16

= 12 + (16 x 2)

= 12 + 32 = 44g/mol

Apply the formula:

Number of molecules = (Mass of CO2 in grams/Molar mass)

2.2x10^9 molecules = Z/44g/mol

Z = 2.2x10^9 molecules x 44g/mol

Z = 9.68 x 10^10g

Thus, the mass of 2.2x10^9 molecules of CO2 is 9.68 x 10^10 grams.

4 0
3 years ago
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})

where,

Q = heat absorbed by metal = 186.75 J

m_1 = Mass of metal= 19 g

T_1 = Initial  temperature of metal = 35^oC

T_2 =Final  temperature of metal = 175^oC

c = specific heat of metal= ?

186.75 J=19 g\times c\times (175^oC-35^oC)

c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

c=0.0702J/g^oC

0.0702J/g°C the specific heat capacity of the metal.

6 0
3 years ago
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