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3 years ago

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

1 answer:

7 0

First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation.

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis:

$4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) = 0.0184 g O_{2}$

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Number 39! Please explain step by step!!!

ahrayia [7]

Answer:

The answer to your question is The honda civic hybrid weights 13181.8 N or 1318.2 kg

Explanation:

Data

Weight = 2900 lb

Weight = ? N

mass = ? kg

1 kg ------- 10 N

0.22lb ---- 1N

Use proportions to solve this problem

0.22 lb ------------------- 1 N

2900 lb ----------------- x

x = (2900 x 1) / 0.22

x = 2900 / 0.22

x = 13181.8 N

1 kg ----------------------- 10 N

x ----------------------- 13181.8 N

x = (13181.8 x 1)/10

x = 1318.2 kg

7 0

3 years ago

For each item, choose whether the change is a physical change or chemical change

Aleonysh [2.5K]

Sorry, but where are the ‘items’?

8 0

3 years ago

What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of

Oksi-84 [34.3K]

The pressure of the gas is obtained as 48 atm.

<h3>What is the total pressure?</h3>

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

Number of moles of H2 = 56.0 grams/2 g/mol = 28 moles

Total number of moles present = 3 moles + 28 moles = 31 moles

Using;

PV =nRT

P = total pressure

V = total volume

n = total number of moles

R = gas constant

T = temperature

P = nRT/V

P = 31 * 0.082 * 286/15

P = 48 atm

Learn more about pressure of a gas:brainly.com/question/18124975

#SPJ1

4 0

1 year ago

One atom of an element possesses 80 protons, 80 electrons, and 121 neutrons. Given this information, what is the atomic mass of

IRINA_888 [86]

Answer:

I think the answer is 4) 41

Explanation:

APE= atomic number, proton and the electrons are the same number

MAN= mass = atomic number - neutrons

121 - 80 = 41

i haven't done this in a while so hope this helps :)

3 0

2 years ago

Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c

malfutka [58]

Answer:

$[F^-]_{max}=4x10{-3}\frac{molF^-}{L}$

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

$Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)$

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

$[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}} \\$

$[F^-]_{max}=4x10{-3}\frac{molF^-}{L}$

Best regards.

8 0

2 years ago