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3 years ago

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

1 answer:

7 0

First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation.

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis:

$4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) = 0.0184 g O_{2}$

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three students made multiple weighings of a copper cylinder each using a different balance. Describe the accuracy and precision

ch4aika [34]

I think that you have put up an incomplete question. However, i am answering the question based on my research and knowledge.

Lissa- accuracy and precision are both low
Lamont- accuracy and precision are definitely high
Leigh Anne- accuracy is low but precision is definitely high.

I hope that this is the answer that you were looking for and the answer has definitely come to your desired help.

3 0

2 years ago

How much water would be needed to completely dissolve 1.52 L of the gas at a pressure of 730 torr and a temperature of 21 ∘C?

Sophie [7]

Answer:

The correct answer is 0.4 L.

Explanation:

The mentioned question can be solved by using the equation,

C = K × Pgas--------(i)

Here K is the Henry law constant whose value is 0.158 mol/L/atm, C is the concentration of the gas in liquid state, and Pgas is the partial pressure of the gas.

Now to find the volume of water, the formula to be used is,

PV = nRT-----------(ii)

Here P is the pressure of the gas, V is the volume, R is the universal gas constant whose value is 0.082 Latm/mol/K and T is the temperature.

PgasV = nRT

Pgas = nRT/Vgas

The value of Pgas is inserted in equation (i) we get,

C = K × nRT/Vgas

It is to be noted that C = n/V, here n is the no. of the moles and V is the volume of liquid.

n/Vliquid = K × nRT/Vgas

1/Vliquid = KRT/Vgas

Vliquid = Vgas/KRT--------------(iii)

Based on the given information, the volume of the gas is 1.52 L, the value of K is 0.158 mol/L/atm, the value of R is 0.082 Latm/mol/K and value of T is 21 degree C or 273 + 21 = 294 K.

Now putting the values in equation (iii) we get,

Vliquid = 1.52 L / 0.158 × 0.082 × 294

Vliquid = 1.52 / 3.809

Vliquid = 0.399 or 0.4 L

Hence, the volume of water required to dissolve 1.52 L of gas is 0.4 L.

8 0

3 years ago

If all the water in 430.0 mL of a 0.45 M NaCI solution evaporates what is the mass of NaCI will remain

skad [1K]

Answer:

11.31 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).

∴ mass of NaCl remained after evaporation of water = (M)(V of the solution (L))(molar mass) = (0.45 M)(0.43 L)(58.44 g/mol) = 11.31 g.

6 0

2 years ago

Read 2 more answers

What does the answer of element 3Na2S2O3?

Fynjy0 [20]

Answer:

Explanation:

3× 22+2×32+ 6×16=

66+64+96=236

4 0

2 years ago

The actual yield of a product in a reaction was measured as 4.20 g. If the theoretical yield of the product for the reaction is

Dmitry_Shevchenko [17]

Answer:

Explanation:

remember the equation percentage yield = actual/ theoretical yield as

4.20/4.88 x 100

86.065 so 86.1.

hope this make sense:)

3 0

2 years ago