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Ronch [10]
3 years ago
9

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

Chemistry
1 answer:
sp2606 [1]3 years ago
7 0
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) =  0.0184 g O_{2}
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