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Alex787 [66]
3 years ago
11

Why can tin (IV) sulfide and antimony (III) sulfide be separated from copper (II) sulfide and bismuth (III) sulfide by the addit

ion of sodium hydroxide
Chemistry
1 answer:
devlian [24]3 years ago
7 0

Answer:

Tin (IV) sulfide and antimony (III) sulfide be separated from copper (II) sulfide and bismuth (III) sulfide by the addition of sodium hydroxide because they become soluble whereas copper (II) sulfide and bismuth (III) sulfide remain insoluble.

Explanation:

Sodium hydroxide is a  basic solution which is used as a precipitating agent for metallic ions in the laboratory.

<em>When a solution containing a mixture of the sulfides of the Group II cations,  antimony (III), copper (II), tin  (IV), and bismuth (III), is made basic by the addition of a base such as sodium hydroxide or ammonium hydroxide, the  sulfide ion concentration will increase. The sulfides of antimony (III) and tin (IV) will then become  soluble because antimony (III) and tin (IV) form stable complexes with sulfide, which are soluble in  water, while the sulfides of copper (II) and bismuth (III) do not.</em> The result is the dissolution of the antimony (III) sulfide  and tin (IV) sulfide, separating them from the copper (II) sulfide and the bismuth (III)  sulfide.

Sb₂S₃(s) + 3S²⁻(aq) ----> 2SbS₃³⁻(aq)

SnS₂(s) + S²⁻(aq) ----> SnS₃³⁻(aq)

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pentagon [3]

Answer:

Explanation:

Heat involved Q = mcΔt where m is mass , c is specific heat of water and Δt is rise in temperature

= 150 x 4.18 x 25.8 J .

= 16176.6 J .

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7 0
3 years ago
Jordan's puppy has a mass of 5480 milligrams , what is the puppy's mass in grams ?
Vesnalui [34]
5480milligrams=5.47×10^1grams

5480×10^-2

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5 0
3 years ago
How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
poizon [28]

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

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<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

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5 0
4 years ago
Match the set of measurements of the boiling point of water with the best
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6 0
4 years ago
Extension: Cedric has been in the hospital for 15 weeks, how many minutes is that? Use
almond37 [142]

Answer:

151200 minutes.

Explanation:

From the question given above, the following data were obtained:

Time (in week) = 15 weeks

Time (in min) =?

Next, we shall convert 15 weeks to days. This can be obtained as follow:

1 week = 7 days

Therefore,

15 weeks = 15 weeks × 7 days / 1 week

15 weeks = 105 days

Next, we shall convert 105 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

105 days = 105 days × 24 h / 1 day

105 days = 2520 h

Finally, we shall convert 2520 h to mins. This can be obtained as follow:

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Therefore,

2520 h = 2520 h × 60 mins / 1 h

2520 h = 151200 mins

Thus, 15 weeks is equivalent to 151200 minutes.

6 0
3 years ago
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