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2 years ago

What is the mass of 2.2x10^9 molecules of CO2? *

Chemistry

1 answer:

olga55 [171]2 years ago

4 0

Answer: 9.68 x 10^10 grams.

Explanation:

Given that:

Mass of CO2 = ?

Number of molecules of CO2 = 2.2x10^9 molecules

Molar mass of CO2 = ? (let unknown value be Z)

For the molar mass of CO2: Atomic mass of Carbon = 12; Oxygen = 16

= 12 + (16 x 2)

= 12 + 32 = 44g/mol

Apply the formula:

Number of molecules = (Mass of CO2 in grams/Molar mass)

2.2x10^9 molecules = Z/44g/mol

Z = 2.2x10^9 molecules x 44g/mol

Z = 9.68 x 10^10g

Thus, the mass of 2.2x10^9 molecules of CO2 is 9.68 x 10^10 grams.

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What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -> 2Hg(l) + O2(g)

Vika [28.1K]

The answer for the following problem is mentioned below.

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO → 2 Hg + $O_{2}$

where,

HgO represents mercuric oxide

Hg represents mercury

$O_{2}$ represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

2×216 grams of HgO → 1 mole of oxygen molecule

? → 0.692 moles of oxygen molecule

= $\frac{2*216*0.692}{1}$

= 298.944 grams of HgO

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

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2 years ago

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Predict the effect of the following changes in the reaction CO (g) + 2 H2 (g) <-> CH3OH (g) + energy.

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Explanation:

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A change in pressure affects only equilibrium involving a gas or gases. Le Chatelier's principle can be used to predict the direction of displacement.

An increase in pressure on an equilibrium system will shift the position of equilibrium to the side having smaller volume and vice-versa

CO + 2H₂ ⇒ CH₃OH + energy

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An increase in pressure will favor the forward reaction to be favored.

b. Addition of H₂:

An in concentration of a specie favors the direction that uses up that specie and lowers its concentration.

Addition of hydrogen gas increases the concentration of amount of substances reacting.

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Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

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<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

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SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

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What is the mass of 2.2x10^9 molecules of CO2? *​

What is the mass of 2.2x10^9 molecules of CO2? *