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ch4aika [34]
3 years ago
10

How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102

5 2.12 × 1025 1.05 × 1025 2.09 × 1025 none of the above
Chemistry
1 answer:
Ede4ka [16]3 years ago
8 0

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles

1 mole of hydrogen (H_2) = 2\times 6.023\times 10^{23}=12.05\times 10^{23} atoms

17.5 mole of hydrogen (H_2) = \frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25} atoms

There are 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

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Answer:

The correct option is E.

Explanation:

Average speed of the gas molecules = v_a

v_a=\sqrt{\frac{2RT}{M}}

T = Temperature of the gas molecule

M = molar mass of gas molecule

R = gas constant

v_a\propto \frac{1}{M}

Higher the molar mass of the molecule lesser will be the speed and vice versa.

Hence, statement A is not true.

Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Larger the molar mass that larger the molecule lessor will be the effusion and vice versa.

Hence, statement B is not true.

According to Boyle's law, pressure of the gas is inversely proportional o the volume occupied by the gas at constant temperature. And same can also be observed from ideal gas law:

PV=nRT

P=\frac{nRT}{V}

P\propto \frac{1}{V}

Higher the pressure of the gas lower will be the volume occupied by the gas and vice versa.

Hence, statement C is not true.

With rise in temperature, effusion of gas molecule increase as kinetic energy of gas molecules increases in with increase in temperature.

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

K=\frac{3RT}{2N_A}

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K = Average kinetic energy

R = Gas constant

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K\propto T

Higher the temperature more will be kinetic energy of gas molecule more easily it will effuse.

Hence, statement D is not true.

From this we can conclude that out of five statements first 4 statements are not true which means that none of these statements are true.

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<h3>Further explanation</h3>

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