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4 years ago

Which process is an example of a physical change?

Physics

1 answer:

svlad2 [7]4 years ago

6 0

Flattening is a example of a physical change.

Hope this helps! :D

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a farmer lifts a bale of hay that is 12m off the ground . If he uses a force of 350 n, how much work does the farmer do?

hjlf

Answer:

4200 Joules

Explanation:

Work done =force x distance

From the question , we’re given f =350N ,

d = 12m

Using the above formula, we have

Workdone = 350 x 12

= 4200 Joules

5 0

3 years ago

The rebirth of science and learning during the fifteenth century is termed the

Pepsi [2]

The Renaissance, was the rebirth to science as well as many other advancements

5 0

4 years ago

The majority of the elements on the periodic table are _______. A. gases B. nonmetals C. metals D. liquids

Paladinen [302]

Option (C) is correct that the majority of the elements on the periodic table are metals.

#$# THANK YOU #$#

7 0

3 years ago

Plan an experiment to measure the ideal mechanical advantage of a three-hole punch. (a) What materials would you need? (b) What

Vaselesa [24]

Answer:

A) Three hole punch and either a layered plastic or paper

B) Identify the lengths involved ,

Length of input arm / length of output arm = L1/ L2

Explanation:

<u>a) Materials involved includes :</u>

Three hole punch and either a layered plastic or paper

Identify the forces acting on the three-hole punch which are Input and output forces

Identify the points where they act

<u>B) procedures involved </u>

The mechanical advantage = output force / input force

step one: Identify the lengths involved

assuming no friction or relatively small friction \

mechanical advantage can be calculated as : Length of input arm / length of output arm = L1/ L2

7 0

3 years ago

N LC circuit has an oscillation frequency of 105 Hz. If C = 0.1 F , then L must be about:

Umnica [9.8K]

Answer:

L = 22.97 H

Explanation:

Given that,

Capacitance, $C=0.1\ \mu F=0.1\times 10^{-6}\ F$

Oscillation frequency, f = 0.5 Hz

The frequency of an AC circuit is given by :

$f=\dfrac{1}{2\pi \sqrt{LC} }$

Where

L is impedance

$f^2=\dfrac{1}{4\pi ^2LC}\\\\L=\dfrac{1}{4\pi ^2 f^2 C}\\\\\text{Putting all the values}\\\\L=\dfrac{1}{4\pi^2 \times (105)^2\times 0.1\times 10^{-6}}\\\\L=22.97\ H$

So, the impedance of LC circuit 22.97 H.

7 0

3 years ago