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3 years ago

Which process is an example of a physical change?

Physics

1 answer:

svlad2 [7]3 years ago

6 0

Flattening is a example of a physical change.

Hope this helps! :D

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A thin, uniform rod is bent into a square of side length a. If the total mass is M, find the moment of inertia about an axis thr

Papessa [141]

Answer:

The moment of inertia about an axis through the center and perpendicular to the plane of the square is

$I_s = \frac{Ma^2}{3}$

Explanation:

From the question we are told that

The length of one side of the square is $a$

The total mass of the square is $M$

Generally the mass of one size of the square is mathematically evaluated as

$m_1 = \frac{M}{4}$

Generally the moment of inertia of one side of the square is mathematically represented as

$I_g = \frac{1}{12} * m_1 * a^2$

Generally given that $m_1 = m_2 = m_3 = m_4 = m$ it means that this moment inertia evaluated above apply to every side of the square

Now substituting for $m_1$

$I _g= \frac{1}{12} * \frac{M}{4} * a^2$

Now according to parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

$I_a = I_g + m [\frac{q}{2} ]^2$

=> $I_a = I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2$

substituting for $I_g$

=> $I_a = \frac{1}{12} * \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2$

=> $I_a = \frac{Ma^2}{48} + \frac{Ma^2}{16}$

=> $I_a = \frac{Ma^2}{12}$

Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

$I_s = 4 * I_a$

=> $I_s = 4 * \frac{Ma^2}{12}$

=> $I_s = \frac{Ma^2}{3}$

8 0

3 years ago

Please help..................

worty [1.4K]

Answer:

PART A

In a solid

The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

In a liquid

Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

A gas

The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.

PART B

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

Explanation:

GOOD LUCK!!! :)

7 0

2 years ago

What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic

Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, $\dfrac{dB}{dt}=3\ T/s$

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

$E=N\dfrac{d\phi}{dt}$

$E=N\dfrac{d(BA)}{dt}$

Since, E = IR

$IR=NA\dfrac{dB}{dt}$

$A=\dfrac{IR}{N.\dfrac{dB}{dt}}$

$A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}$

$A=0.188\ m^2$

$A=0.19\ m^2$

Area of circular cross section is, $A=\pi r^2$

$r=\sqrt{\dfrac{A}{\pi}}$

$r=\sqrt{\dfrac{0.19}{\pi}}$

r = 0.24 m

So, the radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0

3 years ago

The route followed by a hiker consists of three displacement vectors, X, Y and Z. Vector X is along a measured trail and is 1430

poizon [28]

Answer:

magnitude : 1635.43 m
Angle: 130°28'20'' north of east

Explanation:

First, we will find the Cartesian Representation of the $\vec{X}$ and $\vec{Y}$ vectors. We can do this, using the formula

$\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )$

where $| \vec{A} |$ its the magnitude of the vector and θ the angle. For $\vec{X}$ we have:

$\vec{X}= 1430 m \ ( \ cos( 42 \°) \ , \ sin (42 \°) \ )$

$\vec{X}= ( \ 1062.70 m \ , \ 956.86 m \ )$

where the unit vector $\hat{i}$ points east, and $\hat{j}$ points north. Now, the $\vec{Y}$ will be:

$\vec{Y}= - 2200 m \hat{j} = ( \ 0 \ , \ - 2200 m \ )$

Now, taking the sum:

$\vec{X} + \vec{Y} + \vec{Z} = 0$

This is

$\vec{Z} = - \vec{X} - \vec{Y}$

$(Z_x , Z_y) = - ( \ 1062.70 m \ , \ 956.86 m \ ) - ( \ 0 \ , \ - 2200 m \ )$

$(Z_x , Z_y) = ( \ - 1062.70 m \ , \ 2200 m \ - \ 956.86 m \ )$

$(Z_x , Z_y) = ( \ - 1062.70 m \ , \ 1243.14 m\ )$

Now, for the magnitude, we just have to take its length:

$|\vec{Z}| = \sqrt{Z_x^2 + Z_y^2}$

$|\vec{Z}| = \sqrt{(- 1062.70 m)^2 + (1243.14 m)^2}$

$|\vec{Z}| = 1635.43 m$

For its angle, as the vector lays in the second quadrant, we can use:

$\theta = 180\° - arctan(\frac{1243.14 m}{ - 1062.70 m})$

$\theta = 180\° - arctan( -1.1720)$

$\theta = 180\° - 45\°31'40''$

$\theta = 130\°28'20''$

5 0

3 years ago

Which one of the following SI base units is not matched to the correct unit of measurement?

ahrayia [7]

C.Lenth: Km; This answer isn´t correct.

the correct unit of measurement of length is "m".

6 0

3 years ago

Read 2 more answers