All categories

3 years ago

describe how a physical property, such as mass or texture, can change without causing a change in the substance

1 answer:

6 0

On the mass subject you could simply change the weight, on the texture subject you could smooth it out like polishing fresh wood, or you could change the color of water with a drink-mix packet. Hope it helped!

You might be interested in

Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6

Lorico [155]

Answer:

$k=784 N/m$

$\Delta x=8,8 cm$

Explanation:

Usando la ley de Hook tenemos:

$F=k\Delta x$

Solving it for k we have:

$k=\frac{F}{\Delta x}$

$k=\frac{39,2}{0,05}$

$k=784 N/m$

Usando la misma ecuación y sabiendo k tenemos:

$\Delta x=\frac{F}{k}$

$\Delta x=\frac{68,6}{784}$

$\Delta x=8,8 cm$

Espero esto te ayude!

6 0

3 years ago

When we plot all the points that satisfy an equation or inequality we ___ it.

snow_tiger [21]

We use inequalities when there is a range of possible answers for a situation. ... inequalities—inequalities that can be written in the form of a linear equation. ... the bounded region, and anypoint within this region satisfies the inequality x ≥ -2. ... All of the points under the line are shaded; this is the range of points where the ...

6 0

3 years ago

Read 2 more answers

Derivation 1.2 showed how to calculate the work of reversible, isothermal expansion of a perfect gas. Suppose that the expansion

stellarik [79]

Answer:

(a) The work done by the gas on the surroundings is, 17537.016 J

(b) The entropy change of the gas is, 73.0709 J/K

Explanation:

(a) The expression used for work done in reversible isothermal expansion will be,

where,

w = work done = ?

n = number of moles of gas = 4 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = 240 K

= initial volume of gas =

= final volume of gas =

Now put all the given values in the above formula, we get:

The work done by the gas on the surroundings is, 17537.016 J

(b) Now we have to calculate the entropy change of the gas.

As per first law of thermodynamic,

where,

= internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

Thus, w = q = 17537.016 J

Formula used for entropy change:

The entropy change of the gas is, 73.0709 J/K

(c) Now we have to calculate the entropy change of the gas when the expansion is reversible and adiabatic instead of isothermal.

As we know that, in adiabatic process there is no heat exchange between the system and surroundings. That means, q = constant = 0

So, from this we conclude that the entropy change of the gas must also be equal to zero.

Explanation:

6 0

2 years ago

A motorcycle accelerates uniformly from rest at 7.9\,\dfrac{\text{m}}{\text{s}^2}7.9 s 2 m 7, point, 9, space, start fraction,

8090 [49]

Answer:

t = 3.516 s

Explanation:

The most useful kinematic formula would be the velocity of the motorcylce as a function of time, which is:

$v(t) = v_0 +at$

Where v_0 is the initial velocity and a is the acceleration. However the problem states that the motorcyle start at rest therefore v_0 = 0

If we want to know the time it takes to achieve that speed, we first need to convert units from km/h to m/s.

This can be done knowing that

1 km = 1000 m

1 h = 3600 s

Therefore

1 km/h = (1000/3600) m/s = 0.2777... m/s

100 km/h = 27.777... m/s

Now we are looking for the time t, for which v(t) = 27.77 m/s. That is:

27.777 m/s = 7.9 m/s^2 t

Solving for t

t = (27.7777 / 7.9) s = 3.516 s

6 0

3 years ago

A water pump pumps 3 kg of water every second from the bottom of a well to the top of the well 50 m above if the pump used 2000

vesna_86 [32]

watts = work per second.

work is mgh = 3x10x50=1500

watts out = 1500

Watts used = 2000

eff=1500/2000=75%

8 0

3 years ago