Three identical capacitors are connected in parallel to a battery. if a total charge of q flows from the battery, how much charg
1 answer:
Each capacitor carry the same charge 'q'.
Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:
= V₁ +V₂ +V₃
This voltage may also be calculated using capacitance and charge;
V = Q/ C
= V₁ +V₂ +V₃
Provided that the total charge is 'q', hence the total voltage can be expressed as:
= (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)
Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.
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Answer:
the question is incomplete, here is the complete question.
"On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?
1.09 atm
Explanation:
the question addresses an ideal gas. where the relationship between the volume(v),pressure(p),temperature(T) and nos of molecules(n) is expressed as
Where R us the ideal gas constant.
From the question,the number of molecules,volume are constant, we can now re-write the equation as
where pressure and temperature are the only varying parameters.
if we vary the constant K we arrive at
since the Temprature must be in absolute temperature, we add 273k to it Celsius value.
Substituting value into the generated equation, we have