As you inhale, your ribs move up and out decreasing the internal pressure and increasing the volume of the lungs forcing air into the lungs from an area of externally high pressure in comparison to the low internal pressure.
If the length and linear density are constant, the frequency is directly proportional to the square root of the tension.
Answer:
a)
b) 
c)
d) 
e)
f) 
g) p = -5.77 h) q=5
Explanation:
Diagram for given question is attached below in fig 1
<h3>Part (a) (b)</h3>
for vector 
θ = 0°

<h3>Part (c) (d)</h3>
for vector 
θ = 30°

<h3>Part (e) (f)</h3>
for vector 
θ = 90°

<h3>Part (g) (h)</h3>




Total number of Photons = 92.
Radius of the Nucleus = 7.4 x 10^-15 m
Charge of the nucleus = 1.6*10^-19.
Total charge q = 92 x 1.6*10^-19 = 147.2 x 10^-19
k = 9 x 10^9 N m^2 / C^2
Electric field charge E = kq / r^2
=> E = (9 x 10^9 x 147.2 x 10^-19) / (7.4 x 10^-15) ^2
=> (1324.8 x 10^-10) / 54.76 x 10^-30 => 24.19 x 10^20 N/C
Answer:
356°C.
Explanation:
(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.
That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.
(2). The next thing to do is to determine the fourier number.
fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.
(3). The next thing is to determine the temperature at the center plane after 15 s of heating.
The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).
The temperature at the center plane after 15 s of heating = 356°C.