Three identical capacitors are connected in parallel to a battery. if a total charge of q flows from the battery, how much charg
1 answer:
Each capacitor carry the same charge 'q'.
Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:
= V₁ +V₂ +V₃
This voltage may also be calculated using capacitance and charge;
V = Q/ C
= V₁ +V₂ +V₃
Provided that the total charge is 'q', hence the total voltage can be expressed as:
= (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)
Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.
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Answer:
Se the explanation below
Explanation:
We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.
<u>Force exerted by the Earth on a human being</u>
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Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 5.97*10^24[kg]
r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]
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Now replacing we have
<u>Force exerted by a building on a human being</u>
<u />
Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]
r = distance from the building to the person = 2[m]
As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.