Answer:
+17 kg m/s
Explanation:
Question is missing. Found it on google:
"<em>What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg</em>?"
Solution:
we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:
where
is the momentum of the ball before the collision
is the momentum of the pin before the collision (zero because the pin is stationary)
is the momentum of the ball after the collision
is the momentum of the pin after the collision
Solving the equation for , we find:
Answer:
right at negative 1 probably
Explanation:
Answer:
≈ 2.1 R
Explanation:
The moment of inertia of the bodies can be calculated by the equation
I = ∫ r² dm
For bodies with symmetry this tabulated, the moment of inertia of the center of mass
Sphere 
= 2/5 M R²
Spherical shell 
= 2/3 M R²
The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass
I = 
+ M D²
Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation
Let's start with the spherical shell, axis is along a diameter
D = 2R
Ic = + M D²
Ic = 2/3 MR² + M (2R)²
Ic = M R² (2/3 + 4)
Ic = 14/3 M R²
The sphere
Is = + M [²
Is = Ic
2/5 MR² + M ² = 14/3 MR²
² = R² (14/3 - 2/5)
= √ (R² (64/15)
= 2,066 R
Relative motion is the calculation of the motion of an object with regard to some other moving object.
