Answer:
is from 9 x 107 m/sec to 27 x 107 m/s
Answer:
The Magnifying power of a telescope is
Explanation:
Radius of curvature R = 5.9 m = 590 cm
focal length of objective =
⇒ =
⇒ = 295 cm
Focal length of eyepiece = 2.7 cm
Magnifying power of a telescope is given by,
therefore the Magnifying power of a telescope is
Answer:
a) 6076 m
b) 43.33 m/s
c) 68 m/s
Explanation:
(a) If the airplane rounds half the circle in 156s, its displacement is the circle diameter in 156s, or twice the circle's radius
s = 2r = 2* 3.38km = 6.76 km or 6760 m
(b) The average velocity would be displacement over unit of time
v = s/t = 6760 / 156 = 43.33 m/s
(c) The length of the chord it's swept in 156s is half of the circle perimeter
c = πr = π3.38 = 10.62 km or 10620 m
The airplane average speed is its chord length over a unit of time
c / t = c / 156 = 68 m/s
Answer:
Explanation:
If we have a periodic wave we need to satisfy the following basic relationship:
From the last formula we see that the velocity is proportional fo the frequency.
For this case we have the following info given by the problem:
We know that the frequency is the reciprocal of the period so we have this formula:
And if we replace we got:
Now since we have the value for the wavelength we can find the velocity like this:
And if we convert this into cm/s we got: