The tension in the upper rope is determined as 50.53 N.
<h3>Tension in the upper rope</h3>
The tension in the upper rope is calculated as follows;
T(u) = T(d)+ mg
where;
- T(u) is tension in upper rope
- T(d) is tension in lower rope
T(u) = 12.8 N + 3.85(9.8)
T(u) = 50.53 N
Thus, the tension in the upper rope is determined as 50.53 N.
Learn more about tension here: brainly.com/question/918617
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Explanation:
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Answer:
(a) charge q=5.33 nC
(b) charge density σ=10.62 nC/m²
Explanation:
Given data
radius r=0.20 m
potential V=240 V
coulombs constant k=9×10⁹Nm²/C²
To find
(a) charge q
(b) charge density σ
Solution
For (a) charge q
As

For (b) charge density
As charge density σ is given as:
σ=q/(4πR²)
σ=(5.333×10⁻⁹) / (4π×(0.20)²)
σ=10.62 nC/m²