The mass of nitric acid required to make the given solution is 0.0627 g.
The given parameters:
- <em>Volume of the acid, V = 250 mL</em>
- <em>pH of the acid, = 2.4</em>
The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;
![H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398](https://tex.z-dn.net/?f=H%5E%2B%20%3D%2010%5E%7B-pH%7D%5C%5C%5C%5CH%5E%2B%20%3D%2010%5E%7B-2.4%7D%5C%5C%5C%5CH%5E%2B%20%3D%200.00398)
The molarity of the nitric acid is calculated as follows;
![= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M](https://tex.z-dn.net/?f=%3D%20%200.00398%20%5C%20H%5E%2B%20%5Ctimes%20%5Cfrac%7B1%20%5C%20M%20%5C%20HNO_3%7D%7B1%20%5C%20H%5E%2B%7D%20%5C%5C%5C%5C%3D%200.00398%20%5C%20M)
The number of moles of the nitric acid is calculated as follows;
![moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.](https://tex.z-dn.net/?f=moles%20%3D%20M%5Ctimes%20L%5C%5C%5C%5Cmoles%20%3D%200.00398%5C%20M%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B250%20%5C%20mL%7D%7B1000%7D%20%5C%5C%5C%5Cmoles%20%3D%209.95%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20mol.)
The molar mass of nitric acid is calculated as;
![HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol](https://tex.z-dn.net/?f=HNO_3%20%3D%20%281%29%20%5C%20%2B%20%2814%29%20%5C%20%2B%20%2816%20%5Ctimes%203%29%20%3D%2063%20%5C%20g%2Fmol)
The mass of the nitric acid contained in the calculated number of moles is calculated as;
![mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g](https://tex.z-dn.net/?f=mass%20%3D%20moles%5C%20%20%5Ctimes%20%5C%20molar%20%5C%20mass%5C%5C%5C%5Cmass%20%3D%209.95%5Ctimes%2010%5E%7B-4%7D%20%5C%20mol.%20%5C%20%5Ctimes%20%5C%2063%20%5C%20g%2Fmol%5C%5C%5C%5Cmass%20%3D%200.0627%20%5C%20g)
Thus, the mass of nitric acid required to make the given solution is 0.0627 g.
Learn more about molarity of acids here: brainly.com/question/13864682
2-7 days, but depends on the procedure
Ocean-dwelling I would say.
Answer: 0.07868 mol H₂O
Explanation:
1) Chemical equation:
Cu₂O +H₂ → 2Cu + H₂O
2) mole ratios:
1 mol Cu₂O : 1 mol H₂ : 2 mol Cu : 1 mol H₂O
3) Convert 10.00 g of Cu to grams, using the atomic mass:
Atomic mass of Cu: 63.546 g/mol
number of moles = mass in grams / atomic mass = 10.00g / 63.546 g/mol
number of moles = 0.1574 mol
4) Use proportions
2mol Cu 0.1574 mol Cu
--------------- = ---------------------
1 mol H₂O x
⇒ x = 0.1574 mol Cu × 1 mol H₂O / 2mol Cu = 0.07868 mol H₂O
That is the answer
Answer:
water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.
Explanation: