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mash [69]
3 years ago
10

Which of the following BEST explains why the tectonic plates of Earth move?

Chemistry
2 answers:
RoseWind [281]3 years ago
8 0

Answer:

The plates can be thought of like pieces of a cracked shell that rest on the hot, molten rock of Earth’s mantle and fit snugly against one another. The heat from radioactive processes within the planet’s interior causes the plates to move, sometimes toward and sometimes away from each other.

lana66690 [7]3 years ago
4 0

Answer:

The plates can be thought of like pieces of a cracked shell that rest on the hot, molten rock of Earth’s mantle and fit snugly against one another. The heat from radioactive processes within the planet’s interior causes the plates to move, sometimes toward and sometimes away from each other.

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Covert 32 ft/sec^2 to m/min^2
igor_vitrenko [27]

Answer:

Explanation:

585.2 meters per minute in 32 feet per second To convert any value in feet per second to meters per minute, just multiply the value in feet per second by the conversion factor 18.288. So, 32 feet per second times 18.288 is equal to 585.2 m/min.

3 0
3 years ago
What are gases that are molecules
Vinvika [58]

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7 0
3 years ago
You have the equations:
kari74 [83]

Answer:

the answer is 99.0kJ

Explanation:

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7 0
3 years ago
RATE LAW QUESTION !
vivado [14]
In general, we have this rate law express.:

\mathrm{Rate} = k \cdot [A]^x [B]^y
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4)  by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation \Delta \mathrm{Rate} = \Delta [B]^y

3.09 = (3)^y \implies y \approx 1

To this point, \mathrm{Rate} = k \cdot [A]^x [B]^1

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for \Delta \mathrm{Rate} = \Delta [A]^x

4=  (2)^x \implies x = 2

the rate law is

Rate = k·[A]²[B]
6 0
3 years ago
Anything helps thank you
olya-2409 [2.1K]
What do you need help on we need to know the question of your answer...
6 0
3 years ago
Read 2 more answers
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