Too many to know in the world.
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:
ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where:
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3
Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol
m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg
For the problem,
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf
Tf = -1.59 celsius
Solution :
Molar mass of
is :
M = 6×12 + 6×1 g
M = 78 g
78 gram of
contains
molecules.
So, 89.5 gram of
contains :

Now, from the formula we can see that one molecule of
contains 2 hydrogen atom . So, number of hydrogen atom are :

Hence, this is the required solution.
Answer:
Volume of carbon dioxide is 428.23 L.
Explanation:
Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion) and produces carbon dioxide and water as a product in the gaseous form.
The molar mass of undecane = 

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.
Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.



<span>Answer: option D) Conditions over the oceans change slowly because water takes more time than land to gain or lose heat.
This is because water has a high heat capacity meaning that, with the same amount of heat, it will change its temperature less than what substances with lower heat capacities do.
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