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kozerog [31]
3 years ago
9

Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng

th of his electromagnet, he must _____ the number of loops in the coil of wire along its length. If he uses an additional battery, the strength of his electromagnet will _______.
first blank has options: increase, decrease, no change

second blank has the same options
Physics
2 answers:
fenix001 [56]3 years ago
6 0

Answer : The correct answer for both the fill in the blank is, increases.

Explanation :

Formula used :

1) B=\mu_o\times \frac{N\times I}{L}

B = strength of magnetic filed

N = Number of loops

I = current in the wire

\mu_o =  magnetic permeability

B\propto N

The more the number of loops in the solenoid more will the strength of three magnetic fields.

2) Also according to Ohm's law:

Voltage is directly proportional to current:

V\propto I

With increase in voltage the the current will increase which in return increase the magnetic field in the solenoid.

So, the correct answer for both the fill in the blank is, increases.

Rudiy273 years ago
3 0
Answer is increase for both.
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v_f=v_o + at ……..(a)

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Now ,

Initially, there was y velocity, however gravity began to act on the football, causing it to accelerate.  

Applying this value in equation (a)  

v_yf = at = -9.81 m/s^s * 1.75 = -17.165 m/s in the y direction  

For calculating the magnitude of the equation we have to square root the given value

         (16.6i - 17.165y)  

\\ \left | V  \right |=sqrt{16.6^{2}+17.165^{2}}\\ = \sqrt{275.56+294.637225}\\= \sqrt{570.197225}\\= 23.87[/tex]

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3 years ago
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When the area over which pressure is applied is increased,
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3 0
3 years ago
When the mass of the bottle is 0.125 kg, the KE is______ kg m2/s2.
DiKsa [7]
Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
(3) KE = 3 kg m^2/s^2
(4) KE = 4 kg m^2/s^2


Explanation:

(1) Given mass = 0.125 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.125 * (16)
KE = 1 kg m^2/s^2

(2) Given mass = 0.250 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.250 * (16)
KE = 2 kg m^2/s^2

(3) Given mass = 0.375 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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KE = (1/2) * 0.375 * (16)
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(4) Given mass = 0.500 kg
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Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.5 * (16)
KE = 4 kg m^2/s^2
3 0
3 years ago
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