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Bezzdna [24]
3 years ago
7

Need help on 6 and 7 or just one please help

Chemistry
1 answer:
fredd [130]3 years ago
6 0
The forth option on both of them. If you get them wrong, I’m sorry. I’m pretty sure both of these are right thought.
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The answer is A (The ability to react with oxygen)
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Which structure is unique to vertebrates?<br> limbs<br> brain<br> skin<br> backbone
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Organisms that have backbones are known as vertebrates, while the ones without a backbone are classified as invertebrates.

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How many grams of silver sulfide are formed when 0.280 g of hydrogen sulfide reacts with excess silver and oxygen?
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Answer:

2.03~g~Ag_2S

Explanation:

For this question we have to start with the <u>reaction</u>:

Ag~+~H_2S~+~O_2~->~Ag_2S~+~H_2O

Now, we can<u> balance the reaction</u>, so:

4Ag~+~2H_2S~+~O_2~->~2Ag_2S~+~2H_2O

With this in mind, we have to start with the amount of H_2S. The first step is to <u>convert from grams to moles</u>. For this, we need to find the molar mass of H_2S. If we check the periodic table we will find the atomic masses for Ag and H; H: 1 g/mol and A: 32 g/mol, so:

(1*2)+ (32*1) = 34 g/mol.

Now we can <u>calculate the moles</u> of H_2S:

0.280~g~H_2S\frac{34~g~H_2S}{1~mol~H_2S}=0.0082~mol~H_2S

With the moles of H_2S we can calculate the moles of Ag_2S if we check the <u>molar ratio in the balanced equation</u>, 2~mol~H_2S=2~mol_Ag_2S, so:

0.0082~mol~H_2S\frac{2~mol_Ag_2S}{2~mol~H_2S}=0.0082~mol~H_2S

With the molar mass of Ag_2S we can <u>convert from moles to grams</u> (Ag: 107.86 g/mol, S: 32 g/mol), so:

(107.86*1)+(32*2)=247.80 g/mol

0.0082~mol~H_2S\frac{247.8~g~Ag_2S}{1~mol~H_2S}=2.03~g~Ag_2S

I hope it helps!

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