Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
When the the concentrations of both buffer components (the weak acid and its conjugate base) are equal:
[base] = [acid]
So, pH=pKa+log1 = pKa
<u>pH is equal to pKa of weak acid of buffer system
.</u>
When buffer contains more of weak acid than conjugate base:
[base] < [acid]
log [base]/[acid] = Negative,
So,
<u>When more of acid component is present, the pH is more acidic. (It decreases)</u>
When buffer contains more of conjugate base than weak acid:
[base] > [acid]
log [base]/[acid] = Positive,
So,
<u>When more of acid component is present, the pH is more acidic. (It increases)</u>