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balandron [24]
2 years ago
6

Choose all the answers that apply. Oxygen is _____. transported by blood picked up in the alveoli released into the air by the l

ungs pumped to cells by ventricles
Physics
2 answers:
aleksklad [387]2 years ago
4 0
ANSWER:

- Transported by blood picked up in the alveoli
- Pumped to cells by ventricles

Hope this helps! :)
amid [387]2 years ago
4 0

Answer:

The correct answer will be options-

1. transported by blood

2. picked up in the alveoli

3. pumped to cells by ventricles

Explanation:

Oxygen is an important element on earth on which life is dependent as it is the substrate of the important metabolic process of life.

The Oxygen in humans is inhaled and exhaled by breathing which when inhaled gets picked up or exchanged with the connective tissue of the body called blood in the alveoli of the lungs.

The oxygen in the blood is pumped to the body cells by the left ventricle of the heart which along with blood transports the oxygen by binding to haemoglobin in red blood cells.

Thus, the selected option is the correct answer.

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A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob
andre [41]

Answer:

I = -2.1 kg.m/s

Explanation:

Given,

mass of the object,m = 0.30 Kg

initial speed, v_i = 3 m/s

time of collision = 0.20 s

final speed, v_f = -4 m/s

Impulse = change in momentum

I = m (v_f-v_i)

I = 0.30\times (-4-3)

I = -2.1 kg.m/s

Hence, impulse of the object is equal to I = -2.1 kg.m/s

5 0
3 years ago
A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w
salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

Ff = m*a

\mu*N = m*a

\mu*m*g = m*a

a=\mu*g=2.9m/s^2

With a sum of torque on the ball:

Ff*R = I*\alpha

\mu*m*g*R = 2/5*m*R^2*\alpha

\alpha=5/2*\mu*g/R=65.9rad/s^2

Replacing both accelerations:

Vo - a*t=\alpha*t*R

7.5 - 2.9*t=65.9*t*0.11

t=0.74s

The distance will be:

D = Vo*t-1/2*a*t^2

D = 4.76m

Final velocity:

Vf=Vo-a*t

Vf=5.35m/s

7 0
3 years ago
What is the force measured in Newtons between a proton and an electron in the ground state?
goldenfox [79]
The answer is zero hope I helped
5 0
3 years ago
a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​
Dafna1 [17]

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, a_c, is given as follows;

a_c = \dfrac{v^2}{r}

Therefore, the centripetal acceleration of the stone found as follows;

a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2

The centripetal acceleration of the stone, a_c = 5 m/s².

5 0
3 years ago
The human ear is most sensitive to the sounds in what range?
jeyben [28]

Answer:

The human ear is most sensitive to sounds in the range of 2000 to 3000 Hz

3 0
3 years ago
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