Answer:
The extension of the second wire is 
Explanation:
From the question we are told that
The length of the wire is 
The elongation of the wire is 
The tension is 
The length of the second wire is 
Generally the Young's modulus(Y) of this material is

Where 
Where A is the area which is evaluated as

and 
So

Since the wire are of the same material Young's modulus(Y) is constant
So we have


Now the ration between the first and the second wire is

Since tension , radius are constant
We have

substituting values




Because it does not produce waste, thus it doesn't harm the environment. also renewable sources are infinite.
Complete Question
Question 18 (3 points) Solve the problem. (3 points) A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides 2.4m, 2. 3m, 1.5 m. What is the total surface area of the reflector?
A) 33 m2
B) 86 m2
C) 52 m2
D) 34 m2
Answer:
The value is 
Explanation:
From the question we are told that
The sides are a = 2.4 m
b = 2.3 m
c = 1.5 m
Generally the semi perimeter is mathematically represented as

=> 
=> 
Generally the using Heron's formula we have that the surface are a is mathematically represented as

=> 
=> 
The period of a wave is the time it takes the wave to complete one cycle (at a fixed location).
So if a wave completes one cycle in <em>2 seconds</em>, then that is its period.
Answer: small cars can stop and go fast big trucks can not
Explanation: