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3 years ago

HURRY PEASE what happens to current when there is a diode on the circuit and why?

Physics

1 answer:

kolbaska11 [484]3 years ago

6 0

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

Explanation:

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A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented

inn [45]

The E(incident) for the first polarizer is E(incident)=-76.1930384332

The E(incident) for the second polarizer is E(incident)=12.340115991

Explanation:

Solving the problem:

Given

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

1. Through the first polarizer

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first polarizer is E(incident)=-76.1930384332

2. Through the first polarizer

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second polarizer is E(incident)=12.340115991

4 0

3 years ago

A professor sits on a rotating stool that is spinning at 10.0 rpm while she holds a heavy weight in each of her hands. Her outst

USPshnik [31]

Answer:

0.3950m

Explanation:

Use conservation of angular momentum:

Let L be the angular momentum(a vector).

We know that: $p=mv, L=l\omega, \ \ \ l=\sum (m_ir_i^2)}$ and that the two masses have the same radius:

$L_o=2mr_o^2\omega_o=L_f=2mr_f^2\omega_f\\\\r_o=0.795m,\omega_o=10\times2\pi \ rad/m , \omega_f=40.5\times 2\pi \ rad/m\\\\\therefore r_f=r_o\sqrt{(w_o/w_f)}\\\\r_f=0.795\sqrt{(10.0/40.5)}\\\\r_f=0.3950m$

Hence, the weights are 0.3950m away .

6 0

3 years ago

An air bubble has a volume of 1.70 cm³ when it is released by a submarine 115 m below the surface of a lake. What is the volume

Natalija [7]

Answer:

V = 20.67 cm³

Explanation:

In this case, let's apply the Boyle's law which is:

P1V1 = P2V2

Where P1 and V1 would be condition in the water, and P2 and V2 would be the condition at the surface.

By logic, at the surface, pressure should be equals to 1 atm or 1.01x10^5 N/m²

We know the volume of the bubble at first which is 1.70 cm³ and we need to calculate V2. We know how much is P2, but we don't know the value of P1, which is the pressure of the bubble below the sea; this can be calculated using Pascal's principle which is the following expression:

P1 = Po + dgh

Where:

Po: innitial pressure, which we can assume is 1 atm

d = density of the substance, in this case, water (1000 kg/m³)

g = gravity (9.8 m/s²)

h = distance of the bubble from the surface (115 m)

Now replacing this data in the boyle's law we have the following:

P1V1 = P2V2

V2 = P1V1/P2

V2 = (Po + dgh) * V1 / P2

Replacing the data we have:

V2 = (1.01x10^5 + 1000*9.8*115) * 1.7 / 1.01x10^5

V2 = 2,087,600 / 1.01x10^5

V2 = 20.67 cm³

5 0

3 years ago

Who’s good at algebra?

lutik1710 [3]

Answer:

I'm alright................

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Energy can be stored in a magnetic field. True or false?

Rzqust [24]

Your answer is here!

Yes It is true

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