The length of a side of the cube is 21.83 cm.
We need to know about cube volume to solve this problem. Cube volume can be calculated by multiplying the length of the cube. It can be written as
V = L³
where V is cube volume and L is cube length.
From the question above, we know that
V = 11 quart = 2.75 gallon
1 gallon = 3.786 liters
Convert volume to liters
V = 2.75 gallon
V = 2.75 x 3.786 liters
V = 10.41 liters
V = 10.41 dm³
Find the length
V = L³
10.41 = L³
L = ³√10.41
L = 2.18 dm
Convert length to cm
L = 2.183 dm
L = 21.83 cm
Find more on cube volume at: brainly.com/question/1972490
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The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
Answer:
149,916J
Explanation:
Pneumonic device: Kevin is half-mad and very square
this translates to: KE=(1/2)mv^2 !!
KE=(1/2)(78)(62^2)
KE=(39)(3844)
KE=149,916 Joules
Easy !
Take any musical instrument with strings ... a violin, a guitar, etc.
The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.
Pluck any string. Then, slightly twist the tuning peg for that string,
and pluck the string again.
Twisting the peg only changed the string's tension; the length
couldn't change.
-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.
-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
Answer:
Option e
Explanation:
The Law of Universal Gravitation states that every point mass attracts every other point mass in the universe by a force pointing in a straight line between the centers-of-mass of both points, and this force is proportional to the masses of the objects and inversely proportional to their separation This attractive force always points inward, from one point to the other. The Law applies to all objects with masses, big or small. Two big objects can be considered as point-like masses, if the distance between them is very large compared to their sizes or if they are spherically symmetric. For these cases the mass of each object can be represented as a point mass located at its center-of-mass.
The same force is applied to both the balls.
