will give brainliest answer + 20 points! pls help Calculate the volume of solution of 3.6 M NH4Cl needed to prepare 350.0 mL of
1 answer:
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<u>Answer:</u>
3.67 moles
<u>Step-by-step explanation:</u>
We need to find out the number of moles present in 350 grams of a compound.
Molar mass of = 24.305
Molar mass of = 35.453
So, one mole of = 24.305 + (35.453 * 2) = 95.211g
1 Mole in 1 molecule of =
Therefore, number of moles in 350 grams of compound = 0.0105 * 350
= 3.67 moles