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Advocard [28]
3 years ago
5

4 friends go to the fair. They each spend 1/2 of their money on rides.Then they each spend $3 on food. at the end there was $8 t

otal. how much money did each person bring ? show work please
Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer: They each had $22


Step-by-step explanation:

First you do 8+3=11 because that is the other half of the money.

Then you double 11 because they spent 1/2 on rides.

So in the end your answer is $22


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Solution:

Given:

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Thus,

\begin{gathered} For\text{ the point }(-9,-2) \\ x=-9,y=-2 \\ 4x-6y\leq-18 \\ 4(-9)-6(-2)=-36+12=-24 \\ Since\text{ }-24

\begin{gathered} For\text{ the point }(0,3) \\ x=0,y=3 \\ 4x-6y\leq-18 \\ 4(0)-6(3)=0-18=-18 \\ Since\text{ }-18=-18,\text{ then }(0,3)\text{ is a solution} \end{gathered}

\begin{gathered} For\text{ the point }(5,-3) \\ x=5,y=-3 \\ 4x-6y\leq-18 \\ 4(5)-6(-3)=20+18=38 \\ Since\text{ }38>-18,\text{ then }(5,-3)\text{ is not a solution} \end{gathered}

\begin{gathered} For\text{ the point }(8,5) \\ x=8,y=5 \\ 4x-6y\leq-18 \\ 4(8)-6(5)=32-30=2 \\ Since\text{ }2>-18,\text{ then }(8,5)\text{ is not a solution} \end{gathered}

Therefore, the correct answers are selected as shown below;

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1 year ago
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Answer:

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Step-by-step explanation:

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Correct choice is C

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