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3 years ago

When troubleshooting an inoperative power window motor, first check the:

Engineering

1 answer:

Gwar [14]3 years ago

3 0

When troubleshooting an inoperative power window motor, first check the:

fuse for the appropriate circuit. wiring to the motor. switch for the motor ground for the appropriate circuit will be work in the following way.

Explanation:

Use a test light to check the voltage at the motor of the window that is inoperative.

Press the power window switch during the testing process. If there is no voltage at the motor, there may be problems in the wiring that runs from the motor to the switch.
Check for short, loose or open wires.
Causes of power window malfunctions -Window malfunctions are typically caused from either a faulty window regulator (also called a window track), or a broken motor, cable pulley or window switch. Intermittent problems can cause windows to stop working temporarily only to work again and have more problems later.
Symptoms of a Bad or Failing Window Motor / Regulator Assembly. Common signs include having to press multiple times to roll the window up or down, slower or faster window speed, and clicking sounds from the door.
What to Do When Your Power Window Won't Go Up -1.Remove the door panel. 2.Disconnect the window from the motor. 3.Access and disengage the motor. 4.Reconnect the window to the motor and raise. 5.Replace the door panel.
Once your window is all the way down, hold the button down for 2-5 seconds. Release the button after you've held it down for a short period of time. On some vehicles, the required time to reset the window is 2 seconds.

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A simple undamped spring-mass system is set into motion from rest by giving it an initial velocity of 100 mm/s. It oscillates wi

____ [38]

Answer:

f=1.59 Hz

Explanation:

Given that

Simple undamped system means ,system does not consists any damper.If system consists damper then it is damped spring mass system.

Velocity = 100 mm/s

Maximum amplitude = 10 mm

We know that for a simple undamped system spring mass system

$V_{max}=\omega A$

now by putting the values

$V_{max}=\omega A$

100 = ω x 10

ω = 10 rad/s

We also know that

ω=2π f

10 = 2 x π x f

f=1.59 Hz

So the natural frequency will be f=1.59 Hz.

6 0

4 years ago

A plate clutch is used to connect a motor shaft running at 1500rpm to shaft 1. The motor is rated at 4 hp. Using a service facto

vazorg [7]

Answer:

$(M_t)_{rated}=61.11lb-in$

Explanation:

speed of motor (N)=1500 rpm

power=4 hp = $4 \times 0.7457$ =2.9828 KW

service factor(k)= 2.75

now,

$KW=\frac{2\pi n M_t}{60 \times 10^6} \\2.9828=\frac{2\pi \times 1500 M_t}{60 \times 10^6}\\M_t=\frac{2.9828\times 60 \times 10^6}{2\pi \times 1500 }$

$M_t= 18,989.09 \ N-mm= 168.06 lb-in$

torque rating

$(M_t)_{design}=k_s\times (M_t)_{rated}\\168.06= 2.75\times (M_t)_{rated}\\(M_t)_{rated}=\frac{168.06}{2.75} \\(M_t)_{rated}=61.11lb-in$

4 0

4 years ago

Example for strengthening mechanism in single-phase material A. Dispersion strengthening B. Precipitation hardening C. Fiber str

Lena [83]

Answer:

Example for strengthening mechanism in single-phase material: Strain hardening- D.

3 0

3 years ago

Read 2 more answers

While discussing run-flat tires: Technician A says that some are self-sealing tires and are designed to quickly and permanently

musickatia [10]

Answer:

The correct option is d ( Neither A nor B)

Explanation:

Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.

Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.

This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong

Since option a and b are incorrect and c is invalid.

4 0

3 years ago

Refrigerant-134a is to be cooled by water in a condenser. The refrigerant enters

KonstantinChe [14]

Answer:

Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37

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I only know this

sorry for errors

4 0

3 years ago