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Natasha_Volkova [10]
4 years ago
5

Explain the differences between 1- Energy 2- Power 3- Work 4- Heat Your answer should explain the mathematica and physical meani

ng. A thermodynamic example with a nice sketch for each case is a must.

Engineering
1 answer:
vazorg [7]4 years ago
4 0

Answer:

Explanation:

Energy : Energy can be defined as both qualitative and quantitative property that can be given to an object in the form of work or heat.

For example - water stored in a tank at a height,h from the ground has a potential energy of U = ρgh.

Mathematically, Energy of water stored in a tank is

                      U = ρ.g.h

where, ρ is  water density

            g is acceleration due to gravity

            h is height of water tank from ground

Power : Power is defined as rate at which work can be done.

For example - When a force F is applied to an object to move it through a distance d in time t seconds is an example of power delivered.

Mathematically, Power = Work done / Time

                         P = \frac{F\times  d}{t}

                                P = \frac{W}{t}

Work : When a force act on a body and the body moves, work is said to be done.

For example - Gas confined in a cylinder by a piston. The gas expands when it is heated, doing work on the piston.

Mathematically, Work,W = F X d

where, F is force

            d is distance

Heat : Heat is a form of energy which is produced as a result of motion of atoms and particles.

For example - while increasing the temperature of water, heat is added to the water by means of gas burner or any other form.

Mathematically we can calculate heat release or heat absorb by

    q = m.C.ΔT

where q is heat

           m is mass

           C is specific heat capacity

           ΔT is change in temperature

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sveta [45]

Answer:

Explanation:

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6 0
3 years ago
Water flows through a multisection pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s a
Alex_Xolod [135]

Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}

Where:

P_{1}, P_{2} - Pressures at the beginning and at the end of the current line, measured in kilopascals.

\rho - Water density, measured in kilograms per cubic meter.

v_{1}, v_{2} - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

Now, the pressure difference between these two points is:

P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}

If \rho = 1000\,\frac{kg}{m^{3}}, v_{1} = 3\,\frac{m}{s} and v_{2} = 2.1\,\frac{m}{s}, then:

P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}

P_{1} - P_{2} = -2295\,Pa

P_{1} - P_{2} = -2.295\,kPa (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

7 0
3 years ago
End A of the uniform 5-kg bar is pinned freely to the collar, which has an acceleration = 4 m/s2 along the fixed horizontal shaf
sergiy2304 [10]

Answer:

Fa = 57.32 N

Explanation:

given data

mass = 5 kg

acceleration = 4 m/s²

angular velocity ω = 2 rad/s

solution

first we take here moment about point A that is

∑Ma = Iα +  ∑Mad    ...............1

put here value and we get

so here I = ( \frac{1}{12} ) × m × L²    ................2

I = ( \frac{1}{12} ) × 5 × 0.8²

I = 0.267 kg-m²  

and

a  is =  r × α    

a  = 0.4 α

so now put here value in equation is 1

0 = 0.267 α + m r α (0.4) - m A (0.4)

0 = 0.267 α + 5 (0.4α) (0.4 ) - 5 (4) 0.4

so angular acceleration α = 7.5 rad/s²

so here force acting on x axis will be

∑ F(x) = m a(x)    ..............3

a(x) = m a - m rα

put here value

a(x) = 5 × 4 -  5 × 0.4 × 7.5

a(x) = 5 N

and

force acting on y axis will be

∑ F(y) = m a(y)    .............. 4

a(y) - mg = mrω²

a(y) - 5 × 9.81  = 5 × 0.4 × 2²

a(y) = 57.1 N

so

total force at A will be

Fa = \sqrt{a(x)^2+a(y)^2}    ...............5

Fa = \sqrt{(57.1)^2+(5)^2}  

Fa = 57.32 N

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Answer: Increase in the population of lower organisms.

Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.

They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.

Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.

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Whats the thing in the picture? Its a part of a computer.
Digiron [165]

Answer:

Is it part of a computer?

Explanation:

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