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PSYCHO15rus [73]
3 years ago
12

How to conduct electricity with light bulb and battery

Chemistry
2 answers:
BARSIC [14]3 years ago
7 0
Get a lightbulb and holder and wires and battery. Connect the lightbulb to its holder (metal) and clamp the wires onto it, closing the circuit, then touch the other ends of the metal clamps to the battery tips. (A battery holder with metal can also be used.)

lianna [129]3 years ago
5 0

answer:

with a beaker of water with a little bit of oil with 2 metal rods in

just did the quiz

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Elements in the same period of the periodic table exhibit similar physical and chemical properties.
Vladimir [108]

Answer:

same valency electrons

Explanation:

example g 1 elements

5 0
3 years ago
Blood is maintained at a pH of 7.4 by the primary buffers in the plasma and secondary buffers in the erythrocytes. The plasma co
Alinara [238K]

Answer:

74.456.6.4.7.5.3.33-6.57

Explanation:

4 0
4 years ago
What type of element is Hydrogen? Where do you see hydrogen present?
PSYCHO15rus [73]

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em><u>Hydrogen is a chemical and is </u></em><em><u>found in the sun and most of the stars, </u></em><em><u>and the</u></em><em><u> planet Jupiter</u></em><em><u> is composed mostly of hydrogen. On Earth,</u></em><em><u> </u></em><em><u>hydrogen is found in the</u></em><em><u> greatest quantities as water.</u></em>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I hope this helps! /~\

8 0
3 years ago
Which of the following equations are balanced?
Ber [7]

Answer:

I think the first one

Explanation:

I'm not really sure but i count it

3 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
4 years ago
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