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3 years ago

13

What is the maximum number of electrons that can occupy one orbital

2 answers:

olga nikolaevna [1]3 years ago

8 0

Explanation: The first shell can hold 2 electrons and the next one can hold 8. So, if we have an atom like boron which has 5 electrons, we would put 2 electrons in the first shell and we would put our remainder in the second shell.

I will attach an image with a boron atom and with the electrons.

SOVA2 [1]3 years ago

4 0

18 is the max number of electrons in 1 orbital

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Green plants absorbs sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compoun

Serggg [28]

Answer: The frequency of this light is $6.62\times 10^{14}s^{-1}$

Explanation:

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light = $453nm=453\times 10^{-9}m$

c = speed of light = $3.0\times 10^8m/s$

$\nu$ = frequency of light = ?

$\nu=\frac{3.0\times 10^8m/s}{453\times 10^{-9}m}=6.62\times 10^{14}s^{-1}$

The frequency of this light is $6.62\times 10^{14}s^{-1}$

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3 years ago

How many moles of c2h6o are in a 24.5 gram sample?

andreev551 [17]

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3 years ago

REY [17]

Answer:

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3 years ago

weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the

valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 751 mm Hg

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$V_2$ = final volume of gas = ?

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$T_2$ = final temperature of gas = $-27^oC=273-27=246K$

Now put all the given values in the above equation, we get:

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8 0

3 years ago

In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con

klemol [59]

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by = $K_p=0.150$

$Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)$

initial

0 0 0.500 atm

At equilbrium

p p (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

$K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

$0.150=\frac{(0.500-2p)^2}{p\times p}$

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

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3 years ago