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Rasek [7]
3 years ago
8

Drag and drop the terms into the correct locations to describe how the relationship between photosynthetic organisms and animals

based on what they release into the atmosphere. Terms may be used once, more than once, or not at all.'
Photosynthetic bacteria must take in (Blank) to live, and they release (Blank) . Animals must take (Blank) to live, and they release (Blank)

Word Bank:
Carbon Dioxide
Methane
Oxygen
Chemistry
1 answer:
g100num [7]3 years ago
4 0

Answer:

Photosynthetic bacteria must take in <u>Carbon Dioxide</u> to live, and they release <u>Oxygen </u> . Animals must take <u>Oxygen </u> to live, and they release <u>Carbon Dioxide.</u>

Explanation:

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

Photosynthetic bacteria perform same function as plants.  These bacteria contain light harvesting pigments absorb carbon dioxide and release oxygen.

While animals take oxygen and release carbon dioxide to live. This respiration process is opposite to the photosynthesis.

Glucose + oxygen → carbon dioxide + water + 38ATP

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How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is
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5 0
3 years ago
Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
Ostrovityanka [42]

Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

6 0
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