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Karolina [17]
4 years ago
9

A type of transmission line for electromagnetic waves consists of two parallel conducting plates (assumed infinite in width) sep

arated by a distance aaa. Each plate carries the same uniform surface current density of 16.0 A/m, but the currents run in opposite directions. What is the magnitude of the magnetic field between the plates at a point 1.00 mm from one of the plates if aaa
Physics
1 answer:
vekshin14 years ago
8 0

Answer:

2.01 \times 10^{-5}\ T

Complete question:if a = 0.800 cm? (μ0 = 4π × 10-7 T · m/A)

Explanation:

Given:

Distance between plates = 0.8 cm

Distance from one plate = 1 mm

Current density 'J'= 16 A/m

Currents are flowing in opposite direction.

\mu _o=4\pi \times 10^{-7}

When current is flowing in opposite direction then magnetic field given as

B=\dfrac{\mu _oJ}{2}+\dfrac{\mu _oJ}{2}\\B=\mu _oJ

By putting the values we get

B=4\pi \times 10^{-7}\times 16\\B=2.01 \times 10^{-5}\ T

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In the example given below, Aaron applies a force of 300N and Bob applies a force of 450N :
garri49 [273]

Answer:

Explanation:

This problem is all about torque. The "rules" are that in order for a system to be in rotational equilibrium, the sum of the torques on the system have to equal 0 (in other words, they have to equal each other {cancel each other out}). The equation for torque is

τ = F⊥r where τ is torque, F⊥ is the perpendicular force, and r is the lever arm length in meters. We also have to understand that in general Forces moving clockwise are negative and Forces moving counterclockwise are positive. Now we're ready for the problem:

A. The counterclockwise torque:

τ = 300(3) so

τ = 900N*m

B. The clockwise torque:

τ = -450(2.5) so

τ = -1100N*m

C. Obviously the system is not in roational equilibrium because one side is experiencing a greater torque than the other. This system will move clockwise as it currently exists.

D. In order for the system to be in rotational equilibrium, we have to move Bob's location from the fulcrum. Let's see to where.

The torques have to be the same on both sides of the fulcrum; mathematically, that looks like this:

F⊥r = F⊥r  Filling in:

300(3) = 450r and

900 = 450r so

2 = r. This means that Bob will have to move closer to the fulcrum by a half of a meter to 2 meters from the fulcrum in order for the system to be in balance.

Isn't this so much fun?!

3 0
3 years ago
Which best describes a reference frame?
babymother [125]

By definition we have to:

A system or frame of reference are those conventions used by an observer (usually standing at a point on the ground) to be able to measure the position and other physical magnitudes such as speed and acceleration of one or several objects.

The numerical value of some magnitudes can also be relative to the reference system when we refer to the relative movement. There are always mathematical relationships between the observer and the relative magnitudes.

Answer:

C. a position from which something is observed

3 0
4 years ago
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Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively
Ronch [10]

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

For car 1, we have

d_1 = u_1 t + \frac{1}{2}a_1 t^2

where

u_1 = 7 m/s is the initial velocity of car 1

a_1 = 0.4 m/s^2 is the acceleration of car 1

So the equation can be rewritten as

d_1 = 7t + 0.2t^2

For car 2, we have

d_2 = u_2 t + \frac{1}{2}a_2 t^2

where

u_2 = 4 m/s is the initial velocity of car 2

a_2 = 0.5 m/s^2 is the acceleration of car 2

So the equation can be rewritten as

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The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

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And solving for t, we find

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t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

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