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4 years ago

9

A type of transmission line for electromagnetic waves consists of two parallel conducting plates (assumed infinite in width) sep

arated by a distance aaa. Each plate carries the same uniform surface current density of 16.0 A/m, but the currents run in opposite directions. What is the magnitude of the magnetic field between the plates at a point 1.00 mm from one of the plates if aaa

1 answer:

vekshin14 years ago

8 0

Answer:

$2.01 \times 10^{-5}\ T$

Complete question:if a = 0.800 cm? (μ0 = 4π × 10-7 T · m/A)

Explanation:

Given:

Distance between plates = 0.8 cm

Distance from one plate = 1 mm

Current density 'J'= 16 A/m

Currents are flowing in opposite direction.

$\mu _o=4\pi \times 10^{-7}$

When current is flowing in opposite direction then magnetic field given as

$B=\dfrac{\mu _oJ}{2}+\dfrac{\mu _oJ}{2}\\B=\mu _oJ$

By putting the values we get

$B=4\pi \times 10^{-7}\times 16\\B=2.01 \times 10^{-5}\ T$

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3 years ago

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Answer:

Part a)

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Part b)

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Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

$mg - T = ma$

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so we have

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$T = \frac{1}{2}Ma$

now we have

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Part b)

speed of the bucket can be found using kinematics

so we have

$v_f^2 - v_i^2 = 2 a d$

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$v_f = 11.8 m/s$

Part c)

now in order to find the time of fall we can use another equation

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$t = 1.7 s$

Part d)

as we know that cylinder is at rest and not moving downwards

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$F = 42 + (12 \times 9.81)$

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3 years ago

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