Answer:
108 cubic units
Step-by-step explanation:
V = 4 cubic units
v = (1/3)³ = 1/27 cubic units
V/v = 4/(1/27) = 4/1 x 27/1 = 108 cubic units
425 / 50 = 8,5
There you go.
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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