Found a complete text of the above question:
<span>After giving a statistics exam, professor Dang determined the following five number summary for her class results: 57 65 75 88 97
Use this information to draw a box plot of the exam scores. Choose the correct graph below.
57 and 97 serves as the whiskers of the box plot. 57 is the minimum number while 97 is the maximum number.
65 and 88 serves as the ends of the box while 75 is the line found inside the box.
Choices of for the correct graph is attached but my answer is graph B.</span>
Answer:
i will help in a bit
Step-by-step explanation:
Answer:
2 units rep 5cm
Step-by-step explanation:
plz give me brainiest
Answer: the qualifying time in seconds is about 25.3
Step-by-step explanation:
Since the personal best finishing times for a particular race in high school track meets are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = personal best finishing times for a particular race.
µ = mean finishing time
σ = standard deviation
From the information given,
µ = 24.6 seconds
σ = 0.64 seconds
The probability value for the top 15% of finishing time for runners to qualify would be (1 - 15/100) = (1 - 0.15) = 0.85
Looking at the normal distribution table, the z score corresponding to the probability value is 1.04
Therefore,
1.04 = (x - 24.6)/0.64
Cross multiplying by 0.64, it becomes
1.04 × 0.64 = x - 24.6
0.6656 = x - 24.6
x = 0.6656 + 24.6
x = 25.3 seconds
Answer:
y = x-2
Step-by-step explanation:
y = mx + b
3 = 1(5) + b
-2 = b
y = x-2