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Y_Kistochka [10]
3 years ago
7

Polystyrene has dielectric constant 2.6 and dielectric strength 2.0 ×× 10^7 V/m. A piece of polystyrene is used as a dielectric

in a parallel-plate capacitor, filling the volume between the plates.
a. When the electric field between the plates is 80% of the dielectric strength, what is the energy density of the stored energy?
b. When the capacitor is connected to a battery with voltage 500.0 V, the electric field between the plates is 80% of the dielectric strength. What is the area of each plate if the capacitor stores 0.200 mJ of energy under these conditions?
Physics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

(a) 1133J/m

(b) 5.714m²

Explanation:

(a) u = 1/2×εE²

εo = 8.85×10-¹² F/m

E = 0.8 × 2.0×10⁷V/m = 1.6×10⁷V/m

u = 1/2×8.85×10-¹² × (1.6×10⁷)²= 1132.8J/m

(b)

U = 1/2CV² = 1/2(Aεo/d)×V²

U = 1/2(Aεo/d)×V²

U = 200mJ = 200×10-³

d = V/E = 500/ (1.6×10⁷) =3.13×10-⁵m

200×10-³ = 0.5×A×8.85×10-¹²×500²/3.13×10-⁵

200×10-³ = 0.035A

A = 200×10-³/ 0.035 = 5.714m².

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Explanation:

It is given that,

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Since, \Delta p=m\Delta v

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A beam of light converging to the point of 10 cm is incident on the lens. find the position of the point image if the lens has a
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Answer:

beam of light converges to a point A. A lens is placed in the path of the convergent beam 12 cm from P.

To find the point at which the beam converge if the lens is (a) a convex lens of focal length 20 cm, (b) a concave lens of focal length 16 cm

Solution:

As per the given criteria,

the the object is virtual and the image is real (as the lens is placed in the path of the convergent beam)

(a) lens is a convex lens with

focal length, f=20cm

object distance, u=12cm

applying the lens formula, we get

f

1

=

v

1

−

u

1

⟹

v

1

=

f

1

+

u

1

⟹

v

1

=

20

1

+

12

1

⟹

v

1

=

60

3+5

⟹v=7.5cm

Hence the image formed is real, at 7.5cm from the lens on its right side.

(b) lens is a concave lens with

focal length, f=−16cm

object distance, 12cm

applying the lens formula, we get

f

1

=

v

1

−

u

1

⟹

v

1

=

f

1

+

u

1

⟹

v

1

=

−16

1

+

12

1

⟹

v

1

=

48

−3+4

⟹v=48m

Hence the image formed is real, at 48 cm from the lens on the right side.

6 0
3 years ago
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