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3 years ago

The internal energy of a system....

Physics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

C. Equals the sum of all forms of energy contained within the system.

D. Equals the heat entering the system at constant volume.

E. Equals the heat entering the system plus the work done on the system

Explanation:

Internal energy is defined as the sum of internal kinetic energy and internal potential energy, that is, the energy contained within the system.

The first law of thermodynamics relates the change in the internal energy with the heat entering the system (Q) and work done on the system (W), with the following expression:

$\Delta U=Q+W$

If the system is at constant volume the work done is zero. Therefore, the heat entering the system increases its internal energy:

$\Delta U=Q$

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A 2.20-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 29.0 N is require

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Answer:

a. 145 N/m b. 1.29 Hz c. 1.62 m/s d. 0 m e. 13.2 m/s² f. ± 0.2 m g. 2.9 J h. 0.54 m/s i. 4.39 m/s²

Explanation:

a. The force constant of the spring

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b. The frequency of oscillations, f

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c. maximum speed of the object

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v = (√k/m)x where v is the maximum speed of the object

v = (√145/2.2)0.2 = 1.62 m/s

d Where does the maximum speed occur?

The maximum speed occurs at 0 m

e. The maximum acceleration

a = kx/m = 145 × 0.2/2.2 = 13.2 m/s²

f. The maximum acceleration occurs at x = ± 0.2 m

g. The total energy of the system is the maximum elestic potential energy of the system

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h. When x = x₀/3

1/2k(x₀/3)² = 1/2mv²

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v = 1/3(√k/m)x₀ = 1/3(√145/2.2)0.2 = 0.54 m/s

i When x = x₀/3

a = kx₀/3m = 145 × 0.2/(2.2 × 3)= 4.39 m/s²

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